Question

我试图合并一些jsons。我试过these answers，但我认为它们不适合我的需要。

我有2个（或更多）这些jsons

{
    item: {
        icon: "http://services.runescape.com/m=itemdb_rs/4922_obj_sprite.gif?id=2",
        icon_large: "http://services.runescape.com/m=itemdb_rs/4922_obj_big.gif?id=2",
        id: 2,
        type: "Default",
        typeIcon: "http://www.runescape.com/img/categories/Default",
        name: "Cannonball",
        description: "Ammo for the Dwarf Cannon.",
        current: {
            trend: "neutral",
            price: 208
        },
        today: {
            trend: "positive",
            price: "+8"
        },
        members: "true",
        day30: {
            trend: "positive",
            change: "+8.0%"
        },
        day90: {
            trend: "negative",
            change: "-4.0%"
        },
        day180: {
            trend: "positive",
            change: "+9.0%"
        }
    }
}

如何将它们添加到这样的东西？

{
    items: [
        {
            icon: "http://services.runescape.com/m=itemdb_rs/4922_obj_sprite.gif?id=2",
            icon_large: "http://services.runescape.com/m=itemdb_rs/4922_obj_big.gif?id=2",
            id: 2,
            type: "Default",
            typeIcon: "http://www.runescape.com/img/categories/Default",
            name: "Cannonball",
            description: "Ammo for the Dwarf Cannon.",
            //Same other stuff here
        },
        {
            icon: "http://services.runescape.com/m=itemdb_rs/4922_obj_sprite.gif?id=2",
            icon_large: "http://services.runescape.com/m=itemdb_rs/4922_obj_big.gif?id=2",
            id: 2,
            type: "Default",
            typeIcon: "http://www.runescape.com/img/categories/Default",
            name: "Cannonball",
            description: "Ammo for the Dwarf Cannon.",
            //Same other stuff here     
        }
    ]
}

Answer 1

首先，初始JSON字符串无效，密钥没有用双引号括起来，所以我们需要解决这个问题。

使用重复10次的初始字符串的示例代码

<?php

$string = file_get_contents('sample.json');

//var_dump($string);

$data = jsonDecode($string);

for ($i=0;$i<=10;$i++)
    $list['items'][] = $data['item'];

print json_encode($list);

function jsonDecode($string, $assoc=true, $fixNames=true){
  if(strpos($string, '(') === 0){
    $string = substr($string, 1, strlen($string) - 2); // remove outer ( and )
  }
  if($fixNames){
    $string = preg_replace("/(?<!\"|'|\w)([a-zA-Z0-9_]+?)(?!\"|'|\w)\s?:/", "\"$1\":", $string);
  }
  return json_decode($string, $assoc);
}

json修复功能来自这里https://stackoverflow.com/a/17748840/5043552
输出是按要求的

Answer 2

我不知道每个json结构的来源，但我认为它将是可以迭代的东西：

$finalArray = array();
foreach ($jsonStructs as $json)
{
    $j = json_decode($json, true);
    $finalArray['items'][] = $j['item'];
}

$finalJson = json_encode( $finalArray);

我将每个json结构解码为php数组。然后我从中获取项目值并将其放入另一个将保存每个值的数组中。

最后，我将finally数组编码为json，它将为您提供所要求的内容。

我如何添加这些JSONS

2 个答案: