Question

表结构如下

id  dept    salary
1   30  2000
2   20  5500
3   30  6700
4   30  8900
5   30  9900
6   10  1120
7   20  8900
8   10  2400
9   30  2600
10  10  2999

我需要输出有两列：

Id和Salary

Id应该是唯一的，薪水应该有最高薪水

Answer 1

如果同一部门中的其他人没有更高的工资，请使用NOT EXISTS返回epmloyee。

select * from table t1
where not exists (select 1 from table t2
                  where t2.dept = t1.dept
                    and t2.salary > t1.salary)

Core SQL-99，可以与Oracle和Sybase一起使用！

替代解决方案：

select * from table
where (dept, salary) = (select dept, max(salary)
                        from table
                        group by dept)

在Core SQL-2003之外使用以下功能：F641，“行和表构造函数”。（不知道Sybase和Oracle在这里支持什么......）

Answer 2

SELECT ID,Salary FROM TABLE_NAME WHERE SALARY =(SELECT MAX(SALARY) FROM TABLE_NAME)

Answer 3

SELECT a.Id, a.Salary
FROM table a
WHERE a.Salary = (SELECT MAX(Salary) FROM table
                  WHERE Id = a.Id)

Answer 4

select * from (select * from dep order by salary desc, dep, id) t
group by t.dep

Answer 5

使用单次扫描：

WITH SALARIES AS (
    SELECT 1  ID, 30 DEPT, 2000 SALARY FROM DUAL UNION ALL
    SELECT 2  ID, 20 DEPT, 5500 SALARY FROM DUAL UNION ALL
    SELECT 3  ID, 30 DEPT, 6700 SALARY FROM DUAL UNION ALL
    SELECT 4  ID, 30 DEPT, 8900 SALARY FROM DUAL UNION ALL
    SELECT 5  ID, 30 DEPT, 9900 SALARY FROM DUAL UNION ALL
    SELECT 6  ID, 10 DEPT, 1120 SALARY FROM DUAL UNION ALL
    SELECT 7  ID, 20 DEPT, 8900 SALARY FROM DUAL UNION ALL
    SELECT 8  ID, 10 DEPT, 2400 SALARY FROM DUAL UNION ALL
    SELECT 9  ID, 30 DEPT, 2600 SALARY FROM DUAL UNION ALL
    SELECT 10 ID, 10 DEPT, 2999 SALARY FROM DUAL
)
SELECT
    MAX(ID) KEEP (DENSE_RANK LAST ORDER BY SALARY) ID,
    MAX(SALARY) SALARY
FROM
    SALARIES
GROUP BY
    DEPT;

Answer 6

以下三个查询都有效：

select t.dept, t.salary
from
(select dept,max(salary) as m_sal from tempdb..test
group by dept)x, tempdb..test t
where x.dept = t.dept
and x.m_sal = t.salary

select dept, id, salary as m_sal 
from tempdb..test t1
where salary = (select max(salary) from tempdb..test t2 where t2.dept = t1.dept)


select t1.dept,t1.salary from tempdb..test t1 
inner join
(select dept,max(salary) as m_sal from tempdb..test 
group by dept)x on
t1.salary=x.m_sal and
t1.dept=x.dept

在他的部门找到最高薪水的员工

6 个答案: