可运行的示例......

Question

这是我的JPopupMenu的代码以及我如何添加它，它应该在我右键单击表时响应：

   AppDispatcher.register(function (payload) {
                var action = payload.action;
                var text;

                switch (action.actionType) {

                    // Respond to CART_ADD action
                    case FluxCartConstants.CART_ADD:
                        add(action.sku, action.update);
                        break;

                    // Respond to CART_VISIBLE action
                    case FluxCartConstants.CART_VISIBLE:
                        setCartVisible(action.cartVisible);
                        break;

                    // Respond to CART_REMOVE action
                    case FluxCartConstants.CART_REMOVE:
                        removeItem(action.sku);
                        break;

                    default:
                        return true;
                }

                // If action was responded to, emit change event
                thisStore.emitChange();

                return true;

            });

当我右键单击应用程序中的表时，我不确定为什么没有出现弹出菜单。如果有人告诉我我做错了什么，我将不胜感激。

Answer 1

对于不同的操作系统，弹出窗口的触发器是不同的，您不能简单地使用mousePressed而您肯定不应该使用e.getButton() == MouseEvent.BUTTON3

来自How to use Menus, Bringing up a PopupMenu

应该显示弹出菜单的确切手势因外观而异。在Microsoft Windows中，按照惯例，用户通过释放鼠标右键来显示弹出菜单，同时光标位于启用弹出窗口的组件上。在Java外观中，惯用的触发器是按下鼠标右键（对于弹出按钮时释放的弹出按钮）或单击它（对于弹出的按钮）。

相反，您应该检查每个鼠标事件pressed，released和clicked。您还应该使用MouseEvent#isPopupTrigger来确定该事件是否是操作系统的弹出触发器。

说了这么多，我们JComponent#setComponentPopupMenu会更简单，让它决定

personTable.setComponentPopupMenu(popup);

可运行的示例......

import java.awt.Dimension;
import java.awt.EventQueue;
import java.awt.Graphics;
import java.awt.Graphics2D;
import javax.swing.JFrame;
import javax.swing.JMenuItem;
import javax.swing.JPanel;
import javax.swing.JPopupMenu;
import javax.swing.JScrollPane;
import javax.swing.JTable;
import javax.swing.UIManager;
import javax.swing.UnsupportedLookAndFeelException;
import javax.swing.table.DefaultTableModel;

public class Test {

    public static void main(String[] args) {
        new Test();
    }

    public Test() {
        EventQueue.invokeLater(new Runnable() {
            @Override
            public void run() {
                try {
                    UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
                } catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
                    ex.printStackTrace();
                }

                DefaultTableModel model = new DefaultTableModel(10, 10);
                JTable table = new JTable(model);

                JMenuItem mi = new JMenuItem("I'll be your menu for today");
                JPopupMenu popup = new JPopupMenu();
                popup.add(mi);

                table.setComponentPopupMenu(popup);

                JFrame frame = new JFrame("Testing");
                frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
                frame.add(new JScrollPane(table));
                frame.pack();
                frame.setLocationRelativeTo(null);
                frame.setVisible(true);
            }
        });
    }

}

Answer 2

这是无需使用鼠标侦听器即可创建popupMenu的简单方法：

JpopupMenu popMenu = new JpopupMenu() ;
JMenuItem item = new  JMenuItem("my item") ;
popMenu.add(item);
myTable.setComponentPopupMenu(popMenu);

JPopupMenu菜单未显示

2 个答案:

可运行的示例......