Question

由于我喜欢C＃和C ++中的编程，我即将实现类似C＃的事件系统，作为我计划的C ++ SFML-GUI的坚实基础。

这只是我的代码的摘录，我希望这澄清了我的概念：

// Event.h
// STL headers:
#include <functional>
#include <type_traits>
#include <iostream>
// boost headers:
#include <boost/signals/trackable.hpp>
#include <boost/signal.hpp>

namespace Utils
{
    namespace Gui
    {
        #define IMPLEMENTS_EVENT(EVENTNAME, EVENTARGS) public: \
            Utils::Gui::IEvent<EVENTARGS>& EVENTNAME() { return m_on##EVENTNAME; } \
        protected: \
            virtual void On##EVENTNAME(EVENTARGS& e) { m_on##EVENTNAME(this, e); } \
        private: \
            Utils::Gui::Event<EVENTARGS> m_on##EVENTNAME;


        #define MAKE_EVENTFIRING_CLASS(EVENTNAME, EVENTARGS) class Fires##EVENTNAME##Event \
        { \
            IMPLEMENTS_EVENT(EVENTNAME, EVENTARGS); \
        };


        class EventArgs
        {
        public:
            static EventArgs Empty;
        };

        EventArgs EventArgs::Empty = EventArgs();

        template<class TEventArgs>
        class EventHandler : public std::function<void (void*, TEventArgs&)>
        {
            static_assert(std::is_base_of<EventArgs, TEventArgs>::value, 
                "EventHandler must be instantiated with a TEventArgs template paramater type deriving from EventArgs.");
        public:
            typedef void Signature(void*, TEventArgs&);
            typedef void (*HandlerPtr)(void*, TEventArgs&);

            EventHandler() : std::function<Signature>() { }

            template<class TContravariantEventArgs>
            EventHandler(const EventHandler<TContravariantEventArgs>& rhs)
                : std::function<Signature>(reinterpret_cast<HandlerPtr>(*rhs.target<EventHandler<TContravariantEventArgs>::HandlerPtr>())) 
            {
                static_assert(std::is_base_of<TContravariantEventArgs, TEventArgs>::value,
                    "The eventHandler instance to copy does not suffice the rules of contravariance.");
            }

            template<class F>
            EventHandler(F f) : std::function<Signature>(f) { }

            template<class F, class Allocator>
            EventHandler(F f, Allocator alloc) : std::function<Signature>(f, alloc) { }
        };

        template<class TEventArgs>
        class IEvent
        {
        public:
            typedef boost::signal<void (void*, TEventArgs&)> SignalType;

            void operator+= (const EventHandler<TEventArgs>& eventHandler)
            {
                Subscribe(eventHandler);
            }

            void operator-= (const EventHandler<TEventArgs>& eventHandler)
            {
                Unsubscribe(eventHandler);
            }

            virtual void Subscribe(const EventHandler<TEventArgs>& eventHandler) = 0;

            virtual void Subscribe(const EventHandler<TEventArgs>& eventHandler, int group) = 0;

            virtual void Unsubscribe(const EventHandler<TEventArgs>& eventHandler) = 0;
        };

        template<class TEventArgs>
        class Event : public IEvent<TEventArgs>
        {
        public:
            virtual void Subscribe(const EventHandler<TEventArgs>& eventHandler)
            {
                m_signal.connect(*eventHandler.target<EventHandler<TEventArgs>::HandlerPtr>());
            }

            virtual void Subscribe(const EventHandler<TEventArgs>& eventHandler, int group)
            {
                m_signal.connect(group, *eventHandler.target<EventHandler<TEventArgs>::HandlerPtr>());
            }

            virtual void Unsubscribe(const EventHandler<TEventArgs>& eventHandler)
            {
                m_signal.disconnect(*eventHandler.target<EventHandler<TEventArgs>::HandlerPtr>());
            }

            void operator() (void* sender, TEventArgs& e)
            {
                m_signal(sender, e);
            }

        private:
            SignalType m_signal;
        };

        class IEventListener : public boost::signals::trackable
        {
        };
    };
};

正如你所看到的，我正在使用boost :: signal作为我的实际事件系统，但是我将它封装在IEvent接口（实际上是一个抽象类）中，以防止事件监听器通过operator（）触发事件。

为方便起见，我重载了add-assignment和subtract-assignment运算符。如果我现在从IEventListener派生我的事件监听类，我可以编写代码而无需担心信号中的悬空函数指针。

到目前为止，我正在测试我的搜索结果，但我在使用std::tr1::function::target<TFuncPtr>()时遇到了问题：

class BaseEventArgs : public Utils::Gui::EventArgs
{
};

class DerivedEventArgs : public BaseEventArgs
{
};

void Event_BaseEventRaised(void* sender, BaseEventArgs& e)
{
    std::cout << "Event_BaseEventRaised called";
}

void Event_DerivedEventRaised(void* sender, DerivedEventArgs& e)
{
   std::cout << "Event_DerivedEventRaised called";
}

int main()
{
    using namespace Utils::Gui;
    typedef EventHandler<BaseEventArgs>::HandlerPtr pfnBaseEventHandler;
    typedef EventHandler<DerivedEventArgs>::HandlerPtr pfnNewEventHandler;

    // BaseEventHandler with a function taking a BaseEventArgs
    EventHandler<BaseEventArgs> baseEventHandler(Event_BaseEventRaised);
    // DerivedEventHandler with a function taking a DerivedEventArgs
    EventHandler<DerivedEventArgs> newEventHandler(Event_DerivedEventRaised);
    // DerivedEventHandler with a function taking a BaseEventArgs -> Covariance
    EventHandler<DerivedEventArgs> covariantBaseEventHandler(Event_BaseEventRaised);

    const pfnBaseEventHandler* pBaseFunc = baseEventHandler.target<pfnBaseEventHandler>();
    std::cout << "baseEventHandler function pointer is " << ((pBaseFunc != nullptr) ? "valid" : "invalid") << std::endl;

    const pfnNewEventHandler* pNewFunc = newEventHandler.target<pfnNewEventHandler>();
    std::cout << "baseEventHandler function pointer is " << ((pNewFunc != nullptr) ? "valid" : "invalid") << std::endl;

    // Here is the error, covariantBaseEventHandler actually stores a pfnBaseEventHandler:
    pNewFunc = covariantBaseEventHandler.target<pfnNewEventHandler>();
    std::cout << "covariantBaseEventHandler as pfnNewEventHandler function pointer is " << ((pNewFunc != nullptr) ? "valid" : "invalid") << std::endl;

    // This works as expected, but template forces compile-time knowledge of the function pointer type
    pBaseFunc = covariantBaseEventHandler.target<pfnBaseEventHandler>();
    std::cout << "covariantBaseEventHandler as pfnBaseEventHandler function pointer is " << ((pBaseFunc != nullptr) ? "valid" : "invalid") << std::endl;

    return EXIT_SUCCESS;
}

如果TFuncPtr与存储在Functor中的类型完全相同，EventHandler<TEventArgs>::target<TFuncPtr>()方法将只返回有效指针，而不管协方差。由于RTTI检查，它禁止将指针作为标准的弱类型C函数指针访问，这在像这样的情况下很烦人。

EventHandler的类型为DerivedEventArgs，但仍指向pfnBaseEventHandler函数，即使该函数通过构造函数运行。

这意味着，std :: tr1 :: function本身“支持”逆变，但我找不到简单地将函数指针从std :: tr1 :: funcion对象中取出的方法，如果我不这样做知道模板参数所需的编译时的类型。

我希望在这样的情况下，他们添加了一个简单的get（）方法，就像他们为RAII指针类型所做的那样。

由于我对编程很陌生，我想知道是否有办法解决这个问题，最好是在编译时通过模板（我认为这是唯一的方法）。

Answer 1

刚刚找到问题的解决方案。我似乎错过了一个不同地点的演员阵容：

template<class TEventArgs>
class EventHandler : public std::function<void (void*, TEventArgs&)>
{
public:
    typedef void Signature(void*, TEventArgs&);
    typedef void (*HandlerPtr)(void*, TEventArgs&);

    // ...

    template<class TContravariantEventArgs>
    EventHandler(const EventHandler<TContravariantEventArgs>& rhs)
        : std::function<Signature>(reinterpret_cast<HandlerPtr>(*rhs.target<EventHandler<TContravariantEventArgs>::HandlerPtr>())) 
    {
        static_assert(std::is_base_of<TContravariantEventArgs, TEventArgs>::value,
            "The eventHandler instance to copy does not suffice the rules of contravariance.");
    }

    // ...
}

这适用于它应该如何工作。尽管如此，感谢您顺利介绍这个非常棒的社区！

std :: tr1 :: function :: target <tfuncptr>和co- / contravariance </tfuncptr>

1 个答案: