Question

我想制作一组随机数而不重复。

<Basic>
  <Results>
    <Result>a1</Result>
    <Result>a2</Result>
    <Result>a3</Result>
  </Results>
</Basic>

正如你在这里看到的，我有list数组有问题id的值，而且我已经创建了另一个数组，从该数组中随机获得4个元素。但是，我的问题是如何在没有任何重复的Ids的情况下获得这些元素我已经多次尝试过但不幸的是我没有成功。

Answer 1

最简单的事情是改组你的问题ID，然后选择前四个。

Random rnd = new Random();
randomQuestionId = idS.OrderBy(_ => rnd.Next()).Take(4).ToArray();

Answer 2

试试这个，这段代码将生成唯一的随机数

int smallestNumber = 1;
int biggestNumber = 50;

//Determine the amount of random numbers
int amountOfRandomNumbers = 10;

//Create a list of numbers from which the routine
//shall choose the result numbers
var possibleNumbers = new List<int>();
for (int i = smallestNumber; i <= biggestNumber; i++)
    possibleNumbers.Add(i);

var result = new List<int>();

//Initialize a random number generator
Random rand = new Random();

//For-loop which picks each round a unique random number
for (int i = 0; i < amountOfRandomNumbers; i++)
{
     //Generate random number
     int randomNumber = rand.Next(1, possibleNumbers.Count) - 1;  
     result.Add(possibleNumbers[randomNumber]);       
     //Remove the chosen result number from possible numbers list
     possibleNumbers.RemoveAt(randomNumber);
}

//现在循环result并打印输出

Answer 3

var pickFour = array
    .OrderBy(p => Guid.NewGuid())
    .Take(4);

生成无重复的随机数组

3 个答案: