试图计算MDX中的四分位

时间:2015-08-31 05:33:10

标签: mdx cross-join quartile

我的数据如下:

ID                                   |PersonID  |CompanyID  |DateID  |Throughput |AmountType
33F467AC-F35B-4F24-A05B-FC35CF005981 |7         |53         |200802  |3          |0
04EE0FF0-511D-48F5-AA58-7600B3A69695 |18        |4          |201309  |5          |0
AB058AA5-6228-4E7C-9469-55827A5A34C3 |25        |69         |201108  |266        |0

有大约一百万行。列名* ID指的是其他表,因此它们可以用作维度。

我有一个OLAP多维数据集,其中吞吐量为Measure,其余为维度。

我想计算吞吐量测量的四分之一和三。

我遵循了这个指南:https://electrovoid.wordpress.com/2011/06/24/ssas-quartile/ 连同这篇文章:Calculating Quartiles in Analysis Services

我试图使用这个MDX查询:

WITH
SET selection as ([Dates].[Year].&[2014],[Dates].[Month].&[1])  

SET [NonEmptyIds] AS
 NonEmpty(
      [ThroughputID].[ID].[id]
   *[ThroughputID].[ID].[Id].ALLMEMBERS
  ,
  {[Measures].[Throughput]} * [selection]
 )
 SET [ThroughputData] AS 
ORDER
    (    
        [NonEmptyIds],  
        [Measures].[Throughput], 
        BASC
     )
MEMBER [Measures].[RowCount] AS COUNT (ThroughputData)
MEMBER [Measures].[i25] AS ( .25 *  ( [RowCount] - 1 ) ) + 1
MEMBER [Measures].[i25Lo] AS FIX([i25])   - 1
MEMBER [Measures].[i25Rem] AS ([i25] - FIX([i25]))
MEMBER [Measures].[n25Lo] AS (ThroughputData.Item([i25Lo]), [Throughput])
MEMBER [Measures].[n25Hi] AS (ThroughputData.Item([i25Lo] + 1), [Throughput])
MEMBER [Measures].[Quartile1] AS [n25Lo] + ( [i25Rem] * ( [n25Hi] - [Throughput] ))

SELECT
selection ON 0,
[Measures].[Quartile1]
ON 1
FROM (SELECT [Dates].[Y-H-Q-M].MEMBERS ON 0 FROM [Throughput])

但我明白了:'查询(6,7)ID层次结构在Crossjoin函数中被多次使用。'

我是OLAP和MDX的新手。任何想法是什么错误以及我应该如何计算四分位数是正确的?

我在某处读到我需要ID维度,以便在计算Quartiles时能够获得包含所有值而不是聚合值的集合...

1 个答案:

答案 0 :(得分:0)

Culprit是以下代码:

SET [NonEmptyIds] AS
 NonEmpty(
      [ThroughputID].[ID].[id]
   *[ThroughputID].[ID].[Id].ALLMEMBERS
  ,
  {[Measures].[Throughput]} * [selection]
 )

您不能在交叉连接中多次使用相同的层次结构。在这里您使用了[ThroughputID].[ID]两次。而是尝试以下:

SET [NonEmptyIds] AS
 NonEmpty(
      [ThroughputID].[ID].[Id].ALLMEMBERS
  ,
  {[Measures].[Throughput]} * [selection]
 )