如何使用Json.Net?

时间:2015-09-01 04:28:16

标签: c# json json.net datacontract

我在DLL中没有用DataContract, JsonProperty等标记的类。现在我想将类的实例序列化为JSON对象,使用C#属性名称缩短。 / p>

例如,该课程为:

public class Foo
{
    public string SomeLengthyCSharpPropertyName { get; set; }
}
  

我想知道是否可以在C#名称和json名称之间创建映射。我无法直接添加DataContract, JsonProperty属性,如下所示。有没有解决方法?

[DataContract]
public class Foo
{
    [JsonProperty("s")]
    public string SomeLengthyCSharpPropertyName { get; set; }
}

我倾向于不创建另一个具有相同但JsonProperty - 装饰属性的类,并将属性复制到新类,然后序列化。

2 个答案:

答案 0 :(得分:1)

您可以使用成员覆盖属性字典创建自己的自定义ContractResolver,然后覆盖CreateProperty()并将覆盖应用于基类返回的JsonProperty

public class JsonPropertyOverride
{
    public string PropertyName { get; set; }

    public bool? Ignored { get; set; }

    // Others as required from http://www.newtonsoft.com/json/help/html/T_Newtonsoft_Json_JsonPropertyAttribute.htm
    // Changing all value type properties to nullables.
}

public class OverrideContractResolver : DefaultContractResolver
{
    readonly Dictionary<MemberInfo, JsonPropertyOverride> overrides; // A private copy for thread safety.

    public OverrideContractResolver(IDictionary<MemberInfo, JsonPropertyOverride> overrides)
        : base()
    {
        if (overrides == null)
            throw new ArgumentNullException();
        this.overrides = overrides.ToDictionary(p => p.Key, p => p.Value);
    }

    protected override JsonProperty CreateProperty(MemberInfo member, MemberSerialization memberSerialization)
    {
        var property = base.CreateProperty(member, memberSerialization);
        if (property != null)
        {
            JsonPropertyOverride attr;
            if (overrides.TryGetValue(member, out attr))
            {
                if (attr.PropertyName != null)
                    property.PropertyName = ResolvePropertyName(attr.PropertyName);
                if (attr.Ignored != null)
                    property.Ignored = attr.Ignored.Value;
            }
        }
        return property;
    }
}

如果您愿意,也可以继承CamelCasePropertyNamesContractResolver

然后使用它:

public class Foo
{
    public string SomeLengthyCSharpPropertyName { get; set; }

    public string DefaultNotIgnored { get; set; }

    [JsonIgnore]
    public string DefaultIgnored { get; set; }
}

public class TestClass
{
    public static void Test()
    {
        var foo = new Foo { SomeLengthyCSharpPropertyName = "SomeLengthyCSharpPropertyName", DefaultIgnored = "DefaultIgnored", DefaultNotIgnored = "DefaultNotIgnored" };

        var resolver = new OverrideContractResolver(new Dictionary<MemberInfo, JsonPropertyOverride> { 
            { typeof(Foo).GetProperty("SomeLengthyCSharpPropertyName"), new JsonPropertyOverride { PropertyName = "c"  } }, 
            { typeof(Foo).GetProperty("DefaultNotIgnored"), new JsonPropertyOverride { Ignored = true  } }, 
            { typeof(Foo).GetProperty("DefaultIgnored"), new JsonPropertyOverride { Ignored = false  } }, 
        });
        var settings = new JsonSerializerSettings { ContractResolver = resolver };

        var json = JsonConvert.SerializeObject(foo, settings); // Outputs {"c":"SomeLengthyCSharpPropertyName","DefaultIgnored":"DefaultIgnored"}
        Debug.WriteLine(json);

        var expectedJson = @"{ ""c"": ""SomeLengthyCSharpPropertyName"", ""DefaultIgnored"": ""DefaultIgnored"" }";
        var ok = JToken.DeepEquals(JToken.Parse(json), JToken.Parse(expectedJson));
        Debug.Assert(ok); // No assert

        var foo2 = JsonConvert.DeserializeObject<Foo>(json, settings);

        var ok2 = foo2.DefaultIgnored == foo.DefaultIgnored && foo2.SomeLengthyCSharpPropertyName == foo.SomeLengthyCSharpPropertyName;
        Debug.Assert(ok2); // No assert
    }
}

答案 1 :(得分:0)

这绝对是一种解决方法,但您可能想要考虑它。如果该类未被密封,您可以继承它,覆盖它的属性(您想要更改的属性),然后装饰它们。

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