Question

我的C＃mainwindow在单击按钮时启动taskfactory任务。该任务应该从串行设备收集数据，但不仅仅是一次。它应该在＆＃34;实时＆＃34;中收集数据。串行模块向该串行设备发送请求。当设备回答时，它应该将数据返回主窗口（我用事件尝试了它）并再次开始收集数据：开始任务：

private  void menuStartLog_Click(object sender, RoutedEventArgs e)
{
    Librarys.SerialCom Comport = new Librarys.SerialCom();

    Task<string> serialThread = Task<string>.Factory.StartNew(() => Comport.ADVInfo(), TaskCreationOptions.LongRunning);
    textBoxMain.Text = serialThread.Result;
}

此方法称为：

public string ADVInfo()
{
    openConnection();

    if (Comport.IsOpen)
    {
        Comport.DataReceived += new SerialDataReceivedEventHandler(DataReceivedHandler);
        while (true)
        {


            Console.WriteLine("Serial Task started.");
            byte[] SerialRequest = new byte[3] { 0xF0, 0x02, 0x0D };
            Comport.Write(SerialRequest.ToString());

            Console.WriteLine("Serial Thread completed.");


            //Here the task should return data to the mainwindow and request new data
        }     
    }
    return ("No open Comport!!!");
}

private static void DataReceivedHandler(
                    object sender,
                    SerialDataReceivedEventArgs e)
{
    SerialPort sp = (SerialPort)sender;
    string indata = sp.ReadExisting();
    Console.WriteLine("Data Received:");
    Console.Write(indata);
}

但串口通信的线程阻塞了主线程。我可以在主线程中没有等待的情况下返回数据，例如举办活动？

Answer 1

Instead of blocking with .Result, you should await the Task created by StartNew. That way, control is yielded back to the message loop while the operation executes:

private async void menuStartLog_Click(object sender, RoutedEventArgs e)
{
    Librarys.SerialCom Comport = new Librarys.SerialCom();
    Task<string> serialThread = Task<string>.Factory.StartNew(() => Comport.ADVInfo(), TaskCreationOptions.LongRunning);

    textBoxMain.Text = await serialThread;
}

If you want to generate multiple strings from the ComPort, you can return an IEnumerable<string> using yield return.

任务运行时返回数据

1 个答案: