Question

我正在制作一个完整的页面浏览系统，每当有人访问某个页面时，它会添加当前数据及其IP地址。当我去显示特定日期的总行数时，网站只显示没有数字的“行”。代码：

<?php
$servername = "";
$username = "";
$password = "";
$dbname = "";
$date = date("Y-m-d-h-m-s");
$ip = $_SERVER['REMOTE_ADDR'];
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
} 
$date = date("Y-m-d");
$result = mysqli_query("SELECT FROM page_views WHERE date = $date");
$num_rows = mysqli_num_rows($result);

echo "$num_rows Rows\n";

$conn->close();
?>

有人可以说明出了什么问题。

Answer 1

您的查询失败但您不知道，因为您没有检查错误。如果你这样做，你会看到语法错误，因为你省略了SELECT子句中的$result = mysqli_query("SELECT * FROM page_views WHERE date = $date");而你的日期没有引号。

变化：

$result = mysqli_query("SELECT * FROM page_views WHERE date = '$date'");

为：

 <html>
    <!-- google API reference -->
    <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
    <!-- my own script for search function -->

    <center>
    <form method="POST">
        <input type="text" name="search" style="width:400px " placeholder="Search box" onkeyup="searchq();">
        <div id="output">
        </div>
    </form>
    </center>   

      <!-- instant search function -->
 <script type="text/javascript">

function searchq(){
        // get the value
            var txt = $("input").val();
            // post the value
            if(txt){
                $.post("search.php", {searchVal: txt}, function(result){
                    $("#search_output").html(result+"<div id=\"create\" onclick=\"creatq()\"><br>Not found above? Create.</div>");
                });
            }
            else{
                $("#search_output").html("");
            }


        };
function createq(){
    // allert for test purpose: test if the txt has got by the createq function
    alert(txt);
    **$.post( "create_object.php",{creatVal:txt} );**

}

// if enter key pressed, redirect page to the first search result
$("#search").keypress(function(evt){
    if (evt.which == 13) {
       // find the first search result in DOM and trigger a click event 
        var redirectUrl = $('#search_output').find('a').first().attr('href');
        alert(redirectUrl);
      **window.location.href = "www.google.com";
window.location.href = "www.google.com";**
    }
})

</script>
    </html>

mysql结果总数无法正常显示

1 个答案: