WriteLine方法C#

时间:2015-09-06 09:36:45

标签: c# methods

我正在尝试创建一个程序,您可以在其中输入int的值,然后使用方法在该整数中添加或减去数字“10”。问题在于我写的时候:Console.WriteLine("After addition, your value is now {0}",CustomClass.CustomClass'Method); 编译器告诉我,我无法将对象转换为方法。 这是我的代码:

public class CarClass
{

    public static string carModel;

    public static int carSpeed;


    public static void Accelerate()
    {
        carSpeed = carSpeed + 10;
    }
public static void Brake()
    {
        carSpeed = carSpeed - 10;
    }




}
class MainClass
{
    public static void Main(string[] args)
    {

        Console.WriteLine("Enter car model: ");
        CarClass.carModel = Console.ReadLine();

        Console.WriteLine("Enter initial speed: ");
        CarClass.carSpeed = Convert.ToInt32(Console.ReadLine());

        Console.WriteLine("Starting speed of {0} is {1} km/h.", CarClass.carModel, CarClass.carSpeed);
        Console.WriteLine("Now some speed changing...");



Console.WriteLine("After accelerating, new speed of {0} is {1} km/h.",CarClass.carModel,CarClass.carSpeed + CarClass.Accelerate); // here the speed should be starting speed + 10

Console.WriteLine("After accelerating, new speed of {0} is {1} km/h.",CarClass.carModel,CarClass.carSpeed + CarClass.Accelerate); //here the speed should be the previous speed + 10


        Console.ReadLine();

    }
}
}

我不确定这是否是正确的加速方式,因为我需要它来存储先前的值然后再添加“10”。 如果你帮我解决这个问题,我会非常感谢你们。 提前谢谢。

1 个答案:

答案 0 :(得分:3)

您的问题是这个表达式:

CarClass.carSpeed + CarClass.Accelerate

carSpeed是一个整数,Accelerate是一种方法。你不能将数字和方法加在一起,它没有任何意义。

您要做的是执行该方法,该方法将更新carSpeed。然后你可以打印carSpeed的值。如下所示:

CarClass.Accelerate();

Console.WriteLine("After accelerating, new speed of {0} is {1} km/h.", 
    CarClass.carModel, CarClass.carSpeed);
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