如何从linq表达式获取嵌套属性名称（作为展平值）？

Question

我想出了以下内容。但代码看起来不太好：

public static class GenericHelper<TEntity> {

    //This method uses my extension method, but it returns plain property name
    public static string GetPropertyName<TProperty>(Expression<Func<TEntity, TProperty>> propertyExpression) {

        return propertyExpression.GetPropertyName();
    }

    //This method is used to return nested property name as dot-separated value
    public static string GetPropertyFlattenName<TProperty>(Expression<Func<TEntity, TProperty>> propertyExpression) {

        //TODO: check TEntity, if needed. Now it's ignored

        var member = propertyExpression.Body as MemberExpression;

        if (member == null) {
            throw new ArgumentException(String.Format(
                "Expression '{0}' refers to a method, not a property.", propertyExpression));
        }

        var propertyInfo = member.Member as PropertyInfo;

        if (propertyInfo == null) {
            throw new ArgumentException(string.Format(
                "Expression '{0}' refers to a field, not a property.", propertyExpression));
        }

        //Suppposing it's the only one for this method
        var parameter = propertyExpression.Parameters[0].Name;

        return propertyExpression.Body.ToString().Replace(string.Format("{0}.", parameter), "");
    }
}

我发现无法以更智能和更优雅的方式提取扁平属性名称。

只想指定：第一种方法是这样使用的：

GenericHelper<MyEntity>.GetPropertyName(entity => entity.Property)

但是如果我有一个嵌套属性，比如entity.Property.NestedProperty - 我需要使用我的第二种方法：

GenericHelper<MyEntity>.GetPropertyFlattenName(entity => entity.Property.NestedProperty)

返回＆＃34; Property.NestedProperty＆＃34;而不是＆＃34; NestedProperty＆＃34;。