Question

我最近编写了一个脚本，如果我想要监控的网站使用smtplib进行了更改，则会向我发送电子邮件。该程序有效，我收到了电子邮件但是当我查看发送的电子邮件时（因为我自己发送来自同一帐户的电子邮件），它表示没有收件人或“收件人：”地址，只有一个密件抄送地址我希望将电子邮件发送给。这是smtplib的一个特性 - 它实际上并没有添加'To：'地址，只有Bcc地址？代码如下：

if (old_source != new_source):

# now we create a mesasge to send via email
fromAddr = "example@gmail.com"
toAddr = "example@gmail.com"
msg = ""

# smtp login
username = "example@gmail.com"
pswd = "password"

# create server object and login to the gmail smtp
server = smtplib.SMTP_SSL("smtp.gmail.com", 465)
server.login(username, pswd)
server.sendmail(fromAddr, toAddr, msg)
server.quit()

Answer 1

按如下方式更新代码可以解决问题：

if (old_source != new_source):

# now we create a mesasge to send via email
fromAddr = "example@gmail.com"
toAddr = "example@gmail.com"
msg = ""

# smtp login
username = "example@gmail.com"
pswd = "password"

# create server object and login to the gmail smtp

server = smtplib.SMTP_SSL("smtp.gmail.com", 465)
header = 'To:' + toAddr + '\n' + 'From: ' + fromAddr + '\n' + 'Subject:testing \n'
msg = header + msg
server.login(username, pswd)
server.sendmail(fromAddr, toAddr, msg)
server.quit()

Answer 2

尝试手动将任何标题添加到邮件中，并通过空白行与主体分隔，例如：

...
msg="""From: sender@domain.org
To: recipient@otherdomain.org
Subject: Test mail

Mail body, ..."""
...

Answer 3

试试这个，似乎对我有用。

#!/usr/bin/python

#from smtplib import SMTP # Standard connection
from smtplib import SMTP_SSL as SMTP #SSL connection
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText

sender = 'example@gmail.com'
receivers = ['example@gmail.com']


msg = MIMEMultipart()
msg['From'] = 'example@gmail.com'
msg['To'] = 'example@gmail.com'
msg['Subject'] = 'simple email via python test 1'
message = 'This is the body of the email line 1\nLine 2\nEnd'
msg.attach(MIMEText(message))

ServerConnect = False
try:
    smtp_server = SMTP('smtp.gmail.com','465')
    smtp_server.login('#####@gmail.com', '############')
    ServerConnect = True
except SMTPHeloError as e:
    print "Server did not reply"
except SMTPAuthenticationError as e:
    print "Incorrect username/password combination"
except SMTPException as e:
    print "Authentication failed"

if ServerConnect == True:
    try:
        smtp_server.sendmail(sender, receivers, msg.as_string())
        print "Successfully sent email"
    except SMTPException as e:
        print "Error: unable to send email", e
    finally:
        smtp_server.close()

Answer 4

将它扔出去：请尝试menu with tabs。免责声明：我是维护者，但我觉得它可以帮助所有人！

它确实提供了很多默认设置：我非常确定您能够直接发送电子邮件：

import yagmail
yag = yagmail.SMTP(username, password)
yag.send(to_addrs, contents = msg)

还将设置标题：）

您必须首先使用以下任一方式安装yagmail：

pip install yagmail  # python 2
pip3 install yagmail # python 3

一旦你想要嵌入html /图像或添加附件，你真的喜欢这个包！

它还可以防止您在代码中输入密码，从而使其更加安全。

Python smtplib - 发送邮件后没有收件人

4 个答案: