Question

我需要一个特殊的transitionend - 类似事件，在所有转换完成后触发一次，或者如果CSS中没有定义转换则立即触发。

这是我到目前为止所得到的：

(function($){

  $.event.special.transitionsComplete = {

    setup: function(data, namespaces, eventHandle){    
      var queue = [],
          style = window.getComputedStyle(this, null),
          computedProps = style.getPropertyValue('transition-property').split(', '),
          computedDurations = style.getPropertyValue('transition-duration').split(', '),
          $node = $(this);          

      // only count properties with duration higher than 0s
      for(var i = 0; i < computedDurations.length; i++)
        if(computedDurations[i] !== '0s')
          queue.push(computedProps[i]);           

      // there are transitions
      if(queue.length > 0){
        $node.on('webkitTransitionEnd.x transitionend.x', function(e){          
          queue.splice(queue.indexOf(e.originalEvent.propertyName));          
          if(queue.length < 1)
            $node.trigger('transitionsComplete');
        });

      // no transitions, fire (almost) immediately
      }else{
        setTimeout(function(){
          $node.trigger('transitionsComplete');
        }, 5);

      }

    },

    teardown: function(namespaces){
      $(this).off('.x');
    }

  };
})(jQuery);

我做了一个实例here。

唯一的问题是它只有在元素本身具有过渡属性时才有效，忽略了来自子元素的过渡。如果我将transitionsComplete切换到transitionend，则在子转换完成后运行父事件处理程序和子事件处理程序。是否有某种方式，或者更好的方法来确定一个元素是否发生过它或它的孩子的转变？如果可能的话，我想避免手动通过孩子并检查他们的过渡属性。（无论如何这都不可靠，因为即使有些孩子有过渡，也不意味着他们会在那时活跃）

Answer 1

我使用treeWalker api遍历原始节点（root）和所有子节点（仅元素），过滤掉没有过渡的元素，并将过渡属性收集到queue（ fiddle）。正如您所看到的，我已经解决了complete-div和complete-p之间的时差，并且它们现在同时发射（几乎是几毫秒）。

有两个警告，我没有解决方法：

如果存在由不同方式触发的转换，则为示例一是通过将.visible添加到div来触发的其他人通过添加.invisible，将全部添加到queue。事件永远不会激发，因为queue永远不会消失 - 我不知道如何解决这个问题。
如果有快捷方式属性的转换（padding为例如），可能会使用transitionend触发多个transition-property事件，例如padding-top，padding-right等... 会导致数组很快耗尽splice(-1, 1) 从数组末尾删除项目。我有workaround，但是这可能会导致问题，因为它可能会删除其中的其他属性 queue。最好的解决方法是不要在快捷方式上进行转换属性。

treeWalker的代码基于Ban Nadel＆＃39; s Finding HTML Comment Nodes In The DOM Using TreeWalker。

最后的代码：

(function ($) {

    $.event.special.transitionsComplete = {

        setup: function (data, namespaces, eventHandle) {
            var TRANSITION_PROPERTY = 'transition-property';
            var TRANSITION_DURATION = 'transition-duration';

            var root = this;
            var queue = [];
            var $node = $(this);

            function filter(node) { // filter for treeWalker
                /*** filters transitions which are a string with one '0s'. If more then '0s' is defined it will be catched when creating the queue ***/
                var computedDuration = window.getComputedStyle(node, null)
                    .getPropertyValue(TRANSITION_DURATION);

                return computedDuration === '0s' ? NodeFilter.FILTER_SKIP : NodeFilter.FILTER_ACCEPT;
            }

            filter.acceptNode = filter; // for webkit and firefox

            /** create the treeWalker to traverse only elements **/
            var treeWalker = document.createTreeWalker(root, NodeFilter.SHOW_ELEMENT, filter, false);

            /** traverse all elements using treeWalker.nextNode(). First node is the root **/
            do {
                var style = window.getComputedStyle(treeWalker.currentNode, null);
                var computedProps = style.getPropertyValue(TRANSITION_PROPERTY).split(', ');
                var computedDurations = style.getPropertyValue(TRANSITION_DURATION).split(', ');

                /** push all props with duration which is not 0s **/
                computedDurations.forEach(function (duration, index) {
                    duration !== '0s' && queue.push(computedProps[index]);
                });
            } while (treeWalker.nextNode()); // iterate until no next node

            // no transitions, fire (almost) immediately
            if (queue.length === 0) {

                setTimeout(function () {
                    $node.trigger('transitionsComplete');
                }, 5);

                return; // return out of the function to skip the transitions block
            }

            // there are transitions
            $node.on('webkitTransitionEnd.x transitionend.x', function (e) {
                var propertyName = e.originalEvent.propertyName;
                var indexOfProp = queue.indexOf(propertyName);

                queue.splice(indexOfProp, 1);

                if (queue.length < 1) {
                    console.log('Transitions Complete');
                    $node.trigger('transitionsComplete');
                }
            });

        },

        teardown: function (namespaces) {
            $(this).off('.x');
        }

    };
})(jQuery);

Answer 2

if($('div').one('webkitTransitionEnd otransitionend oTransitionEnd msTransitionEnd transitionend')) {
  $('div').one('webkitTransitionEnd otransitionend oTransitionEnd msTransitionEnd transitionend', function(e) {
    console.log("Fire after transitions");
  });
} else {
  console.log("Fire immediately if there are no transitions");
}

我确信有人会解释为什么这样的实现不起作用，但也许会提供一些灵感/讨论。

https://jsfiddle.net/nf8gvbuo/16/

Answer 3

所以，你去，确实我检查了孩子们：http://jsfiddle.net/cegejk59/2/

(function($){

  $.event.special.transitionsComplete = {

    setup: function( data, namespaces, eventHandle ) {

        var allTransitions          = [];
            w                       = window,
            TRANSITION_PROPERTY_KEY = 'transition-property',
            TRANSITION_DURATION_KEY = 'transition-duration',
            $node                   = $( this );

        function collectTransitionsRecursively( node ) {

            var style                   = w.getComputedStyle( node ),
                nodeComputedProperties  = style.getPropertyValue( TRANSITION_PROPERTY_KEY ).split( ', ' ),
                nodeComputedDurations   = style.getPropertyValue( TRANSITION_DURATION_KEY ).split( ', ' );

            for( var i = 0; i < nodeComputedDurations.length; i++ )
                if( nodeComputedDurations[ i ] !== '0s' )
                    allTransitions.push( nodeComputedProperties[ i ] );

            for( var childIndex = 0; childIndex < node.children.length; childIndex++ )
                collectTransitionsRecursively( node.children[ childIndex ] );
        }

        function triggerTransitionsComplete( $onNode ) {

            console.log( "No transitions (left)." );

            $onNode.trigger('transitionsComplete');
        }

        function onNoTransitionsFound() {

            setTimeout( function() {

                triggerTransitionsComplete( $node );
            });
        }

        collectTransitionsRecursively( this );

        if( allTransitions.length == 0 )
            return onNoTransitionsFound();
        else
            console.log( 'remaining', allTransitions );    

        $node.on('webkitTransitionEnd.x transitionend.x', function( e ){ 

            allTransitions.splice(allTransitions.indexOf(e.originalEvent.propertyName));

            if( allTransitions.length == 0 )
                triggerTransitionsComplete( $node );
            else
                console.log('remaining', allTransitions);
        });
    },

    teardown: function( namespaces ) {

      $( this ).off( '.x' );
    }
  };
})(jQuery);


var div = $('div'), p = $('p'), start = new Date().getTime();
console.log('-- start --');
div.addClass('visible');

div.one('transitionsComplete', function(e){
    console.log('complete-div', (new Date().getTime() - start) / 1000);
});

//p.one('transitionsComplete', function(e){
//    console.log('complete-p', (new Date().getTime() - start) / 1000);
//});

Answer 4

$(function() {

  var div = $("div"),
    p = $("p"),
    start = new Date().getTime();
  console.log("-- start --");
  div.addClass("visible");

  var n = 0
  , transitions = [];
  div.on({
    "transitionend": function(e) {
      ++n;
      transitions.push({
        "element": e.originalEvent.srcElement,
        "property": e.originalEvent.propertyName,
        "duration": e.originalEvent.elapsedTime
      });
      var container = $(this).css("transition").split(","),
        elems = $(p, this).css("transition").split(",");
      if (container.length === 1 && n === elems.length) {
        $(this).trigger("transitionComplete", [transitions])
      }
    },
    "transitionComplete": function(e, tx) {
      console.log(e.type, this, (new Date().getTime() - start) / 1000, tx);
      alert(e.type);
    }
  });

});

p {
  opacity: 0;
  transition: opacity 10s, transform 5s;
  background: red;
  width: 50px;
  height: 50px;
  margin: 100px;
}
div.visible p {
  opacity: 1;
  transform: scale(1.5);
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

<div>
  <p></p>
</div>

jsfiddle http://jsfiddle.net/nf8gvbuo/1/

一个“过渡”事件，总是触发，只有一次

4 个答案: