Question

我试图使用此代码获取SSID

import Foundation
import SystemConfiguration.CaptiveNetwork

public class SSID {
    class func getSSID() -> String{
        var currentSSID = ""
        let interfaces = CNCopySupportedInterfaces()
        if interfaces != nil {
            let interfacesArray = interfaces.takeRetainedValue() as [String : AnyObject]
            if interfacesArray.count > 0 {
                let interfaceName = interfacesArray[0] as String
                let unsafeInterfaceData = CNCopyCurrentNetworkInfo(interfaceName)
                if unsafeInterfaceData != nil {
                    let interfaceData = unsafeInterfaceData.takeRetainedValue() as Dictionary!
                    currentSSID = interfaceData[kCNNetworkInfoKeySSID] as! String
                    let ssiddata = NSString(data:interfaceData[kCNNetworkInfoKeySSIDData]! as! NSData, encoding:NSUTF8StringEncoding) as! String
                    // ssid data from hex
                    print(ssiddata)
                }
            }
        }
        return currentSSID
    }
}

但在此行中收到错误 let interfacesArray = interfaces.takeRetainedValue() as [String : AnyObject]

错误是

Value of type 'CFArray?' has no member 'takeRetainedValue'

感谢您的帮助

Answer 1

这可能会对你有帮助（在Swift 2上测试）：

import Foundation
import SystemConfiguration.CaptiveNetwork

public class SSID {
    class func fetchSSIDInfo() -> String {
        var currentSSID = ""
        if let interfaces = CNCopySupportedInterfaces() {
            for i in 0..<CFArrayGetCount(interfaces) {
                let interfaceName: UnsafePointer<Void> = CFArrayGetValueAtIndex(interfaces, i)
                let rec = unsafeBitCast(interfaceName, AnyObject.self)
                let unsafeInterfaceData = CNCopyCurrentNetworkInfo("\(rec)")
                if unsafeInterfaceData != nil {
                    let interfaceData = unsafeInterfaceData! as Dictionary!
                    currentSSID = interfaceData["SSID"] as! String
                }
            }
        }
        return currentSSID
    }
}

我接受并调整了Ray Wenderlich网站的代码（曾经在这里： Retrieve SSID in iOS9但现在特定线程已从网站中删除了

iOS 12

您必须从功能启用Access WiFi信息。

重要要在iOS 12及更高版本中使用此功能，请在Xcode中为您的应用启用Access WiFi信息功能。启用此功能后，Xcode会自动将Access WiFi信息权利添加到您的权利文件和应用程序ID中。 Documentation link

<强> Swift4.2

public class SSID {
    class func fetchSSIDInfo() -> String {
        var currentSSID = ""
        if let interfaces = CNCopySupportedInterfaces() {
            for i in 0..<CFArrayGetCount(interfaces) {
                let interfaceName: UnsafeRawPointer = CFArrayGetValueAtIndex(interfaces, i)
                let rec = unsafeBitCast(interfaceName, to: AnyObject.self)
                let unsafeInterfaceData = CNCopyCurrentNetworkInfo("\(rec)" as CFString)
                if let interfaceData = unsafeInterfaceData as? [String: AnyObject] {
                    currentSSID = interfaceData["SSID"] as! String
                    let BSSID = interfaceData["BSSID"] as! String
                    let SSIDDATA = interfaceData["SSIDDATA"] as! String
                    debugPrint("ssid=\(currentSSID), BSSID=\(BSSID), SSIDDATA=\(SSIDDATA)")
                }
            }
        }
        return currentSSID
    }
}

Answer 2

这是我的解决方案 Swift 3 iOS 10 ，它适用于 Xcode 8

import Foundation

import SystemConfiguration.CaptiveNetwork

class network : NSObject {

    func getSSID() -> String? {

        let interfaces = CNCopySupportedInterfaces()
        if interfaces == nil {
            return nil
        }

        let interfacesArray = interfaces as! [String]
        if interfacesArray.count <= 0 {
            return nil
        }

        let interfaceName = interfacesArray[0] as String
        let unsafeInterfaceData =     CNCopyCurrentNetworkInfo(interfaceName as CFString)
        if unsafeInterfaceData == nil {
            return nil
        }

        let interfaceData = unsafeInterfaceData as! Dictionary <String,AnyObject>

        return interfaceData["SSID"] as? String
    }

}

使用它：

let wifiName = network().getSSID()

    guard wifiName != nil else {

        //// TODO: Alert -----
        print("no wifi name")

        return
    }


    print("my network name is: \(wifiName!)")

PS：注意它不适用于模拟器

Answer 3

此刻呈现的所有解决方案看起来相当复杂，丑陋的不安全演员阵容。

我能够制作出如此简洁的解决方案（根本没有黑魔法）：

import Foundation
import SystemConfiguration.CaptiveNetwork

func getSSID() -> String? {
    var ssid: String?
    if let interfaces = CNCopySupportedInterfaces() as NSArray? {
        for interface in interfaces {
            if let interfaceInfo = CNCopyCurrentNetworkInfo(interface as! CFString) as NSDictionary? {
                ssid = interfaceInfo[kCNNetworkInfoKeySSID as String] as? String
                break
            }
        }
    }
    return ssid
}

Answer 4

在Swift 3中（适用于真实设备和模拟器）：

import SystemConfiguration.CaptiveNetwork

internal class SSID {
    class func fetchSSIDInfo() ->  String {
        var currentSSID = ""
        if let interfaces:CFArray = CNCopySupportedInterfaces() {
            for i in 0..<CFArrayGetCount(interfaces){
                let interfaceName: UnsafeRawPointer = CFArrayGetValueAtIndex(interfaces, i)
                let rec = unsafeBitCast(interfaceName, to: AnyObject.self)
                let unsafeInterfaceData = CNCopyCurrentNetworkInfo("\(rec)" as CFString)
                if unsafeInterfaceData != nil {

                    let interfaceData = unsafeInterfaceData! as Dictionary!
                    currentSSID = ((interfaceData as? [String : AnyObject])?["SSID"])! as! String

                }
            }
        }
        return currentSSID
    }
}

用法：

SSID.fetchSSIDInfo()

//will return "" if no connected wifi or running in simulator

Answer 5

在swift 2中，您不必致电takeRetainedValue。

将代码interfaces.takeRetainedValue() as [String : AnyObject]替换为Array(arrayLiteral: interfaces)。

另请记住将代码interfacesArray[0] as String更改为String(interfacesArray[0])。

完整代码：

public class SSID {
class func getSSID() -> String{
    var currentSSID = ""
    let interfaces = CNCopySupportedInterfaces()
    if interfaces != nil {
        let interfacesArray = Array(arrayLiteral: interfaces)
        if interfacesArray.count > 0 {
            let interfaceName =  String(interfacesArray[0])
            let unsafeInterfaceData = CNCopyCurrentNetworkInfo(interfaceName)
            if unsafeInterfaceData != nil {
                let interfaceData = unsafeInterfaceData.takeRetainedValue() as Dictionary!
                currentSSID = interfaceData[kCNNetworkInfoKeySSID] as! String
                let ssiddata = NSString(data:interfaceData[kCNNetworkInfoKeySSIDData]! as! NSData, encoding:NSUTF8StringEncoding) as! String
                // ssid data from hex
                print(ssiddata)
            }
        }
    }
    return currentSSID
}

}

Answer 6

Swift 4版本

import SystemConfiguration.CaptiveNetwork


func getSSID() -> String? {
    guard let interface = (CNCopySupportedInterfaces() as? [String])?.first,
        let unsafeInterfaceData = CNCopyCurrentNetworkInfo(interface as CFString) as? [String: Any],
        let ssid = unsafeInterfaceData["SSID"] as? String else{
            return nil
    }
    return ssid
}

Answer 7

以下函数返回wifi名称和Mac地址

    func getNetworkInfo()->(success:Bool,ssid:String,mac:String){
      var currentSSID:String = ""
      var macAdrees:String = ""
      var succes:Bool = false
      let interfaces:CFArray! = CNCopySupportedInterfaces()
      for i in 0..<CFArrayGetCount(interfaces){
        let interfaceName: UnsafePointer<Void>
        =  CFArrayGetValueAtIndex(interfaces, i)
        let rec = unsafeBitCast(interfaceName, AnyObject.self)
        let unsafeInterfaceData = CNCopyCurrentNetworkInfo("\(rec)")
        if unsafeInterfaceData != nil {
            let interfaceData = unsafeInterfaceData! as Dictionary!
            currentSSID = interfaceData["SSID"] as! String
            macAdrees = interfaceData["BSSID"] as! String
            succes = true
        } else {
            currentSSID = ""
        }
    }

    return (succes, currentSSID, macAdrees)
}

此代码工作正常。您将在开发目标＆gt; = iOS9

中注意到一些警告

Answer 8

https://stackoverflow.com/users/3108877/rob的答案 - 更短的版本

func getSSID() -> String? {
        if let interface = (CNCopySupportedInterfaces() as? [String])?.first,
            let unsafeInterfaceData = CNCopyCurrentNetworkInfo(interface as CFString) as? [String: Any],
            let ssid = unsafeInterfaceData["SSID"] as? String {
            return ssid
        }
        return nil
    }

Answer 9

你可以找到另一个答案，更新了Swift标准的@japes答案，它支持 Swift 3 和 Swift 4 。在模拟器上返回空""。

import SystemConfiguration.CaptiveNetwork

internal class SSID {

    class func fetchSSIDInfo() -> String {
        var currentSSID = ""
        if let interfaces = CNCopySupportedInterfaces() {
            for i in 0..<CFArrayGetCount(interfaces){
                let interfaceName = CFArrayGetValueAtIndex(interfaces, i)
                let rec = unsafeBitCast(interfaceName, to: AnyObject.self)
                guard let unsafeInterfaceData = CNCopyCurrentNetworkInfo("\(rec)" as CFString) else {
                    return currentSSID
                }
                guard let interfaceData = unsafeInterfaceData as? [String: Any] else {
                    return currentSSID
                }
                guard let SSID = interfaceData["SSID"] as? String else {
                    return currentSSID
                }
                currentSSID = SSID
            }
        }
        return currentSSID
    }

}

Answer 10

在Swift中抓取WiFi网络的SSID和BSSID

我已经使用SystemConfiguration框架看到了这个非常受欢迎的问题的许多版本。仔细阅读这份答案清单，我发现它们无处不在。不安全的位转换，魔术弦，奇怪的强制。每当API返回CFArray或CFDictionary时，请使用免费桥接获取NS{Array,Dictionary}。它使您可以避免CoreFoundation的某些较丑陋的方面（在Swift中）。同样，您应该使用标头中定义的用于SSID和BSSID字典值的常量。这里绝对不需要Unsafe类型，所有数据类型都是定义良好的。就是说，此代码的CaptiveNetwork版本已在iOS 14中弃用，建议您改用NetworkExtension框架。

NEHotspotNetwork

import NetworkExtension

NEHotspotNetwork.fetchCurrent { hotspotNetwork in
    if let ssid = hotspotNetwork?.ssid {
        print(ssid)
    }
}

已弃用-CaptiveNetwork方法

import SystemConfiguration.CaptiveNetwork

func getWiFiNetwork() -> (ssid: String, bssid: String)?
{
    var wifiNetwork: (ssid: String, bssid: String)?
    if let interfaces = CNCopySupportedInterfaces() as NSArray? {
        for interface in interfaces {
            let name = interface as! CFString
            if let interfaceData = CNCopyCurrentNetworkInfo(name) as NSDictionary? {
                if let ssid = interfaceData[kCNNetworkInfoKeySSID] as? String,
                    let bssid = interfaceData[kCNNetworkInfoKeyBSSID] as? String {
                    wifiNetwork = (ssid: ssid, bssid: bssid)
                }
            }
        }
    }
    
    return wifiNetwork
}

权限-CoreLocation

就用户权限而言，您有可能，但您需要在文档中为CNCopyCurrentNetworkInfo或fetchCurrent定义的四个之一-在大多数情况下，我认为您需要添加CoreLocation并请求权限使用用户的位置。例如，Info.p列表中的Privacy - Location When In Use Usage Description需要您要求用户位置的原因，然后必须进行呼叫以请求用户授权对话框。

    import CoreLocation

    CLLocationManager().requestWhenInUseAuthorization()

权利

您的应用还需要权利-com.apple.developer.networking.wifi-info，该权利已添加到项目的“ 签名和功能”部分中，称为“ 访问WiFi信息”。使用NEHotspotNetwork方法时，还需要附加的网络扩展权利。

在Swift 2中获取SSID

10 个答案:

在Swift中抓取WiFi网络的SSID和BSSID

NEHotspotNetwork

已弃用-CaptiveNetwork方法

权限-CoreLocation

权利