Question

我有这段代码：

function initialize() {

	  var myLatlng = new google.maps.LatLng(0.0, 0.0);
            var myOptions = {
                zoom:7,
                center: myLatlng,
                mapTypeId: google.maps.MapTypeId.ROADMAP
            }
          var  map = new google.maps.Map(document.getElementById("cluster_map"), myOptions);
    refreshMap();
}





function refreshMap() {
    if (markerClusterer) {
        markerClusterer.clearMarkers();
    }
    $.getJSON(__cfg('json_data_url'), function(data) {
        if (data) {
            for (var i = 0; i < data['Properties']['Count']; i ++ ) {
                updateClusterMarker(data['Properties'][i]['Property'].latitude, data['Properties'][i]['Property'].longitude, data['Properties'][i]['Property'].id, i, 'Property');
            }
            for (var i = 0; i < data['Requests']['Count']; i ++ ) {
                updateClusterMarker(data['Requests'][i]['Request'].latitude, data['Requests'][i]['Request'].longitude, data['Requests'][i]['Request'].id, i, 'Request');
            }
            var zoom = null;
            var size = null;
            var style = null;
            markerClusterer = new MarkerClusterer(map, markers, {
                maxZoom: zoom,
                gridSize: size,
                styles: styles[style]
			});
        }
    });
}
function updateClusterMarker(lat, lang, id, count, type) {
	var imageUrl = __cfg('path_relative') + 'img/R.png';
    if (type == 'Property') {
        var imageUrl = __cfg('path_relative') + 'img/P.png';
    }
    var markerImage = new google.maps.MarkerImage(imageUrl, new google.maps.Size(32, 32));
    var latLng = new google.maps.LatLng(lat, lang);
    eval('var marker' + count + ' = new google.maps.Marker({position: latLng,draggable: false,icon: markerImage});');
    eval('marker' + count + '.count=1');
    markers.push(eval('marker' + count));
	var embed_url = __cfg('path_relative') + 'requests/get_info/' + id;
    if (type == 'Property') {
        var embed_url = __cfg('path_relative') + 'properties/get_info/' + id;
    }
    var contentString = '<iframe src="' + embed_url + '" width="279" height="120" frameborder = "0" scrolling="no">Loading...</iframe>';
    eval('var infowindow' + count + ' = new google.maps.InfoWindow({ content: contentString,  maxWidth: 300});');
    var infowindow_obj = eval('infowindow' + count);
    var marker_obj = eval('marker' + count);
    google.maps.event.addListener(marker_obj, 'click', function() {
        infowindow_obj.open(map, marker_obj);
    });
}

它工作得很好，但是当我试图将地图中心与标记相同时，它将无法工作。我试过这段代码：

	  var myLatlng = new google.maps.LatLng(lat, lang);

有谁知道如何将地图置于与标记相同的位置？任何帮助将不胜感激。

感谢

Answer 1

您可以使用.getPosition()方法获取标记位置（它返回LatLng类对象）。因此，您可以使用类似map.panTo(marker.getPosition());

的内容

示例（jsFiddle）：

window.onload = function(){
    var map = new google.maps.Map(document.getElementById('map'), { 
        center: new google.maps.LatLng(22.669, 77.709),
        zoom: 5,
        mapTypeId: google.maps.MapTypeId.ROADMAP
    });

    var marker = new google.maps.Marker({
        position: new google.maps.LatLng(22.669, 77.709),
        map: map
    });

    $('button').on('click', function(){
        map.panTo(marker.getPosition());
    });
};

Answer 2

我终于明白了：

styles.xml

为谷歌地图获取坐标Latlng

2 个答案: