Question

您好我正在尝试开发一个看似容易做的报告，其中有人可以输入ID号或名称并搜索和检索数据。只有在我拥有所有标准的情况下，我才能使这个工作正常，而且我尝试了几种不同的方法。 First，Last和ID中的每一个都是用于填写或留空的框。在没有浪费大量空间的情况下，我基本上已经完成了，任何人都可以帮忙吗？

联：

Select 
worker_id as "ID",
worker_last_name as "Last",
worker_first_name as "First",
worker_phone_home as "Home_Phone",
worker_email as "Email"
from worker
where worker_id = :parm_EB_pnum --inputvalue
UNION
Select 
worker_id as "ID",
worker_last_name as "Last",
worker_first_name as "First",
worker_phone_home as "Home_Phone",
worker_email as "Email"
from worker
where (
upper(worker_first_name) like upper(:parm_EB_first) and 
upper(worker_last_name) like upper(:parm_EB_last)
)

我也尝试使用=而不是类似的结果，我需要两个输入。我在没有UNION的where子句中尝试了一个CASE语句，但我得到了相同的结果

Answer 1

使用%时，您应该使用like。此外，where条件or就足以满足您的要求。您还可以执行trim删除输入值中的任何空格。

select 
worker_id as "ID",
worker_last_name as "Last",
worker_first_name as "First",
worker_phone_home as "Home_Phone",
worker_email as "Email"
from worker
where worker_id = :parm_EB_pnum
or upper(worker_first_name) like '%'||upper(:parm_EB_first)||'%' 
or upper(worker_last_name)  like '%'||upper(:parm_EB_last)||'%'

Answer 2

尝试

Select 
worker_id as "ID",
worker_last_name as "Last",
worker_first_name as "First",
worker_phone_home as "Home_Phone",
worker_email as "Email"
from worker
where worker_id = (CASE WHEN :parm_EB_pnum > 0 THEN :parm_EB_pnum END) 
UNION
Select 
worker_id as "ID",
worker_last_name as "Last",
worker_first_name as "First",
worker_phone_home as "Home_Phone",
worker_email as "Email"
from worker
where 
upper(worker_first_name) like ( CASE WHEN :parm_EB_first IS NOT NULL THEN upper(:parm_EB_first) END)
and upper(worker_last_name) like ( CASE WHEN :parm_EB_last IS NOT NULL THEN upper(:parm_EB_last) END)

按ID或名称进行联合查询

2 个答案: