Question

这是我的代码：

#include <iostream>
#include <stdexcept>
#include <vector>
#include <stdio.h>
#include <stdlib.h>
using namespace std;

struct TeamS 
{
    int ID;
    string MEMBERS[3];
};
//Vector initialization
void Initialize (vector<TeamS> & TeamV, const int id[], const string m[][3], int arraySize)
{
    for(int i=0 ; i<4 ; i++)
    {
        TeamV.at(i).ID = id[i];
        for(int j=0 ; j<3 ; j++)
        {   
            TeamV.at(i).MEMBERS[j]=m[i][j];

        }
    }
}

void printList (const vector <TeamS>& TeamV)
{
     for(int i=0 ; i<4; i++)
    {
        cout<<"Information for team "<<i<<endl;
        cout<<TeamV[i].ID;
        for(int j=0 ; j<3 ; j++)
        {   
            cout<<"      "<<TeamV[i].MEMBERS[j]<<"     ";
        }
        cout<<endl;
    }
}

int main(int argc, char** argv) 
{
    short int choice;
    cout<<"Starting Initialization"<<endl;
    vector<TeamS> TeamV;
    const int ID [4] ={ 123, 321, 456, 789};
    const string MEMBERS [4] [3] =  {    {"Sarah", "Joe", "John"}, {"Chris", "Kevin", "James"}, {"Tom", "Kim", "Emily"}, {"Jill", "Jason", "Jim"}   };
    cout<<"Ending Initialization"<<endl;
    Initialize (TeamV, ID ,MEMBERS, 4);
    cout<<"**** Team List **** "<<endl;
    //printList(TeamV);
    cout<<"************************************************************************"<<endl;

    while(1)
    {
    cout<<"Enter 1 to see a list of teams"<<endl;
    cout<<"Enter 2 to add a team to the list"<<endl;
    cout<<"Enter 3 to search for a team using an ID"<<endl;
    cout<<"Enter 4 to end the program"<<endl;
    cout<<endl<<"Enter Choice : ";
    cin>>choice;
    if(choice == 1)
              {  printList(TeamV);  }
    else if(choice == 2)
              {                     }
    else if(choice ==3 )
              {                     }
    else if(choice == 4)
              {  exit(0);           }
    }

    return 0;
}

每当我编译它时，它会给我错误终止程序'std：out_of_range' 什么＆lt;＆gt ;: vector :: _ M_range_check 我在代码中找不到问题，但看看你可能有什么东西

Answer 1

你真的没有在你的矢量上添加任何东西。您的Initialize()以：

开头

TeamV.at(i).ID = id[i];

但如果TeamV为空，则会抛出out_of_range。你可能打算这样做：

TeamV.push_back(TeamS()); // NOW, there's something in it
TeamV[i].ID = id[i];

更好的是将构造函数添加到带有id和某些成员的TeamS，以便循环可以是：

for (int i = 0; i < 4; ++i) {
    TeamV.push_back(TeamS(id[i], m[i]));
}

或者在C ++ 11中：

std::vector<TeamS> TeamV{
    {123, {"Sarah", "Joe", "John"}},
    {321, {"Chris", "Kevin", "James"}},
    ...
};

Answer 2

您似乎在主函数中创建了矢量TeamV并将其留空。它没有任何元素。但是你打电话给Initialize(TeamV,...)。在这您试图通过at()访问TeamV的元素，但它是空的！

std :: out_of_range：vector :: _ M_range_check

2 个答案: