BeautifulSoup检测NoFollow

Question

我正在寻找BeautifulSoup来检测链接中的NoFollow / DoFollow。是否有捷径可寻？我正在寻找一个忽略区分大小写的选项，并以不同的方式使用rel = nofollow。

我有这个，但它不起作用：

        if 'nofollow' in link:
            print "Nofollow"
        else:
            print "Dofollow"

编辑：其实我弄清楚了，这是代码：

        if link in soup.find_all(rel="nofollow"):
            print "NoFollow"
        else:
            print "Dofollow"

似乎它正在运行，我会更多地测试它并编辑是否需要例外。

Answer 1

links = soup.find_all(rel=True)  # This will find all links which has an attribute named 'rel'
for link in links:
    print link['rel']   # This will print the value of rel attribute while looping through the earlier found links