Question

我想在时间戳上汇总一列。

这是一个例子：

表包含col1，col2，...，col_ts（时间戳列）等列。

SELECT
SUM(col1) OVER (ORDER BY col_ts ROWS BETWEEN 2 PRECEDING AND 2 FOLLOWING) SUM1,
SUM(col2) OVER (ORDER BY col_ts ROWS BETWEEN 2 PRECEDING AND 2 FOLLOWING) SUM2
FROM ...

现在，当时间戳之间的差异<= 5分钟时，我只需要2个PRECEDING和2个下行行。

例如，让我们看一下这些时间戳值：

14.09.15 15:44:00
14.09.15 15:50:00
14.09.15 15:51:00
14.09.15 15:52:00
14.09.15 15:53:00

什么时候在时间戳值＃34; 14.09.15 15：51：00＆＃34;的行中，我希望SUM值从15:50到15:53，因为15之间的差异：50和15:44大于5分钟。

有没有办法在over子句中写出这样的条件？

或者有没有人能够提供良好且高效的解决方案？

Answer 1

好的，我在这里看到了问题。谢谢弗罗林。那么一些预处理呢？我可以找到解决方案，但我不确定是否有更快的解决方案：

select col_ts, 
       n, 
       SUM(n) OVER (ORDER BY col_ts ROWS BETWEEN LEFT_VALUE PRECEDING AND RIGHT_VALUE FOLLOWING) MY_SUM,
       SUM(n) OVER (ORDER BY col_ts RANGE BETWEEN interval '5' second PRECEDING AND interval '5' second FOLLOWING) OLD_SUM
from (
       select col_ts,
              n,
              CASE
              WHEN (LEAD(col_ts,1) OVER (ORDER BY col_ts ) - col_ts) <= INTERVAL '5' second 
              THEN 
                   CASE
                   WHEN (LEAD(col_ts,2) OVER (ORDER BY col_ts ) - LEAD(col_ts,1) OVER (ORDER BY col_ts )) <= INTERVAL '5' second 
                   THEN 2 
                   ELSE 1
                   END
             ELSE 0
             END AS RIGHT_VALUE,
             CASE 
             WHEN (col_ts - LAG(col_ts,1) OVER (ORDER BY col_ts ) ) <= INTERVAL '5' second 
             THEN 
                  CASE 
                  WHEN (LAG(col_ts,1) OVER (ORDER BY col_ts ) - LAG(col_ts,2) OVER (ORDER BY col_ts )) <= INTERVAL '5' second 
                  THEN 2 
                  ELSE 1
                  END
            ELSE 0
            END AS LEFT_VALUE
      from fg_test
  );

结果：

COL_TS                           N   MY_SUM      OLD_SUM
---------------------------  -----  -------  -----------
15.09.15 09:34:24,069000000      1        6            6
15.09.15 09:34:28,000000000      2       10           15
15.09.15 09:34:29,000000000      3       15           15
15.09.15 09:34:30,000000000      4       14           14
15.09.15 09:34:31,000000000      5       12           14
15.09.15 09:34:37,000000000      6        6            6

你觉得怎么样？

Answer 2

I think it's too much for sql. You can restrict the number or elements in window, you can restrict somehow(see bellow) the values, but not both at the same time.

drop table fg_test;
create table fg_test(col_ts timestamp, n number);

insert into fg_test values (systimestamp, 1);
insert into fg_test values (systimestamp+4/1440/60, 2);
insert into fg_test values (systimestamp+5/1440/60, 3);
insert into fg_test values (systimestamp+6/1440/60, 4);
insert into fg_test values (systimestamp+7/1440/60, 5);
insert into fg_test values (systimestamp+13/1440/60, 6);

select col_ts, n, 
  SUM(n) OVER (ORDER BY col_ts ROWS BETWEEN 1 PRECEDING AND 1 FOLLOWING) SUM1,
  SUM(n) OVER (ORDER BY col_ts RANGE BETWEEN current row AND interval '5' second FOLLOWING) SUMNEW
from fg_test;

Results:

COL_TS                                   N       SUM1       SUM2
------------------------------- ---------- ---------- ----------
14-SEP-15 06.16.28.825395000 PM          1          3          3 
14-SEP-15 06.16.33.000000000 PM          2          6         14 
14-SEP-15 06.16.34.000000000 PM          3          9         12 
14-SEP-15 06.16.35.000000000 PM          4         12          9 
14-SEP-15 06.16.36.000000000 PM          5         15          5 
14-SEP-15 06.16.42.000000000 PM          6         11          6

(sorry for not taking the exact example as in your question)

The alternative is to write some PL/SQL(open a cursor and do some processing).

限制oracle中over语句中的数据

2 个答案: