Question

我有一个有两列的表; EVENT_DATE日期和RANG数字第一列包含事件的日期，而第二列包含该事件的期间。这是一个数据样本

| EVENT_DATE | RANG |
|------------|------|
| 03/01/2015 |    1 |
| 09/04/2015 |    3 |
| 15/10/2015 |    2 |

有没有办法通过基于EVENT_DATE值递增RANG来扩展| EVENT_DATE | |------------| | 03/01/2015 | | 04/01/2015 | | 09/04/2015 | | 10/04/2015 | | 11/04/2015 | | 12/04/2015 | | 15/10/2015 | | 16/10/2015 | | 17/10/2015 |，所以输出就像，

{{1}}

Answer 1

你走了。

select to_char(event_date + (l - 1),'dd/mm/yyyy') from tab1 t
left outer join (
  select level l from dual
  connect by level <= (select max(rang) + 1 from tab1)
) on l <= rang + 1
order by event_date, 1;

SQL Fiddle

Answer 2

这应该有效：

select (t.event_date + t2.value) as event_date
from t, (select rownum -1 as value from all_objects) t2
where t2.value <= t.rang
order by 1 asc;

Answer 3

另一个可能的答案。假设myObj["foo"] = []是你的表

Event1

根据列值展开表行

3 个答案: