Question

我正在尝试创建一个PDO查询构建器类，但它在更新功能中不起作用。我收到错误：

警告：PDOStatement :: execute（）：SQLSTATE [HY093]：参数号无效：绑定变量数与令牌数不匹配

任何人都可以告诉我如何让它发挥作用。感谢

class query extends PDO {

private $_statement;
private $_prepare;

public function __construct() {
    parent::__construct(DB_TYPE . ':host=' . DB_HOST . ';dbname=' . DB_NAME, DB_USER, DB_PASS);
    $this->_statement = "";
    $this->_prepare = NULL;
}

function UPDATE($table) {
    $this->_prepare = $this->prepare("UPDATE " . $table);
    $this->_statement = $this->_prepare->queryString;
    return $this;
}

function DATA($data) {
    ksort($data);
    if (strstr($this->_statement, "UPDATE")) {
        $fieldDetails = null;
        foreach ($data as $key => $value) {
            $fieldDetails.="$key = :$key, ";
        }
        $fieldDetails = rtrim($fieldDetails, ', ');
        $this->_prepare = $this->prepare($this->_statement . " SET " . $fieldDetails);
        foreach ($data as $key => $value) {
            $this->_prepare->bindValue(":$key", $value);
        }
    }
    $this->_statement = $this->_prepare->queryString;
    return $this;
}

function WHERE($where, $operator = "AND") {
    $condition = null;
    if (is_array($where)) {
        if (count($where) != 0) {
            foreach ($where as $key => $value) {
                $condition.="$key = :$tempK " . $operator . " ";
            }
        }
    }
    $condition = rtrim($condition, $operator . " ");

    $this->_prepare = $this->prepare($this->_statement . " WHERE " . $condition);
    foreach ($where as $key => $value) {
        $this->_prepare->bindValue(":$tempK", $value);
    }
    $this->_statement = $this->_prepare->queryString;
    return $this;
}

function send() {
    return  $this->_prepare->execute();
    }
}

这是测试功能

$q = new query();
$q->UPDATE("user")
->DATA(array("email" => "dd"))
->WHERE(array("username"=>"ee"))
->send();

Answer 1

谢谢你们，我自己找到了一个解决方案，想分享我的解决方案。

这是代码更新

    class query extends PDO {

private $_statement;
private $_prepare;
private $_values;

public function __construct() {
    parent::__construct(DB_TYPE . ':host=' . DB_HOST . ';dbname=' . DB_NAME, DB_USER, DB_PASS);
    $this->_statement = "";
    $this->_prepare = NULL;
    $this->_values = array();
}

function UPDATE($table) {
    $this->_prepare = $this->prepare("UPDATE " . $table);
    $this->_statement = $this->_prepare->queryString;
    return $this;
}

function DATA($data) {
    ksort($data);
    if (strstr($this->_statement, "UPDATE")) {
        $fieldDetails = null;
        foreach ($data as $key => $value) {
            $fieldDetails.="$key = :$key, ";
        }
        $fieldDetails = rtrim($fieldDetails, ', ');
        $this->_prepare = $this->prepare($this->_statement . " SET " . $fieldDetails);
        foreach ($data as $key => $value) {
            $this->_values[":$key"] = $value;
        }
    }
    $this->_statement = $this->_prepare->queryString;
    return $this;
}

function WHERE($where, $operator = "AND") {
    $condition = null;
    if (is_array($where)) {
        if (count($where) != 0) {
            foreach ($where as $key => $value) {
                $condition.="$key = :where$key " . $operator . " ";
            }
        }
    }
    $condition = rtrim($condition, $operator . " ");

    $this->_prepare = $this->prepare($this->_statement . " WHERE " . $condition);
    foreach ($where as $key => $value) {
        $this->_values[":where$key"] = $value;
    }
    $this->_statement = $this->_prepare->queryString;
    return $this;
}

function send() {
    return  $this->_prepare->execute($this->_values);
    }
}

我认为问题可能是 prepare语句不能在单独的函数中使用bindValue（）。 execute（）的参数也允许我将所有绑定值放入prepare语句中。最后，问题解决了。

PDO查询构建器类execute（）错误SQLSTATE [HY093]：无效的参数编号：绑定变量的数量与标记的数量不匹配

1 个答案: