我有这个MySQL查询。但是，我想知道为什么我收到此错误消息。
'where子句'中的未知列'min_pp_distance'
我很确定我在查询中有这个变量。
IF(PP.latitude <> 0 AND PP.longitude <> 0, ( 6371 * acos( cos( radians(3.5951956) ) * cos( radians( PP.latitude ) ) * cos( radians( PP.longitude ) - radians(98.6722227) ) + sin( radians(3.5951956) ) * sin( radians( PP.latitude ) ) ) ) , 9999999) as min_pp_distance
这是完整的查询（我整理并删除一些不必要的变量）
SELECT SQL_CALC_FOUND_ROWS D.id * -1 as id, D.doc_title as doc_title,
NULL as user_email, D.first_name, D.last_name,
...
CONCAT_WS('#', PP.id, PP.name) as pp_name, CONCAT_WS('#', PP.id, PP.address)
as pp_address, CONCAT_WS('#', PP.id, PP.phone) as pp_phone, CONCAT_WS('#',
PP.id, V.name)as pp_vil, CONCAT_WS('#', PP.id, SD.name) as pp_sub_d,
CONCAT_WS('#', PP.id, C.name) as pp_city, CONCAT_WS('#', PP.id, P.name) as
pp_province, CONCAT_WS('#', PP.id, PP.zipcode) as pp_zip, 1 pp_is_primary,
CONCAT_WS('#', PP.id, PP.latitude) as pp_lat, CONCAT_WS('#', PP.id,
PP.longitude) as pp_lng, CONCAT_WS('#', PP.id, PP.type) as pp_type,
CONCAT_WS('#', PP.id,
IF(PP.latitude <> 0 AND PP.longitude <> 0, ( 6371 *
acos( cos( radians(3.5951956) ) * cos( radians( PP.latitude ) ) * cos(
radians( PP.longitude ) - radians(98.6722227) ) + sin( radians(3.5951956) )
* sin( radians( PP.latitude ) ) ) ), 0)) as pp_distance, IF(PP.latitude <> 0 AND PP.longitude <> 0, ( 6371 * acos( cos( radians(3.5951956) ) * cos(radians( PP.latitude ) ) * cos( radians( PP.longitude ) -
radians(98.6722227) ) + sin( radians(3.5951956) ) * sin( radians(
PP.latitude ) ) ) ) , 9999999) as min_pp_distance,
....
D.status as reg_status FROM register_doctor D LEFT JOIN
ref_doctor_practice_place RDPP ON RDPP.doctor_id = D.id * -1 LEFT JOIN
practice_place PP ON PP.id = RDPP.practice_place_id LEFT JOIN village V ON
V.id = PP.village_id LEFT JOIN sub_district SD ON SD.id =PP.sub_district_id
LEFT JOIN city C ON C.id = SD.city_id INNER JOIN province P ON P.id =
PP.province_id INNER JOIN city RDC ON RDC.id = D.city_id AND RDC.name LIKE
'%Medan%' INNER JOIN province RDP ON RDP.id = RDC.province_id AND ( RDP.name
LIKE 'Sumatera Utara%' OR RDP.long_name LIKE 'Sumatera Utara%' ) INNER JOIN
...
WHERE D.status = 2 AND min_pp_distance < 50 OR min_pp_distance = 9999999 GROUP BY D.id ORDER BY min_pp_distance ASC, RAND() LIMIT 0,10
这是CREATE TABLE：
CREATE TABLE IF NOT EXISTS `register_doctor` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`doc_title` int(11) NOT NULL,
`first_name` varchar(35) NOT NULL,
`last_name` varchar(35) DEFAULT NULL,
`gender` int(11) NOT NULL,
`city_id` int(11) NOT NULL,
`province_id` int(11) NOT NULL,
`status` int(11) NOT NULL COMMENT '0 = Pending; 1 = Verified, 2 = Not Reg Yet, 3 = Pending Approval',
`str_number` char(6) DEFAULT NULL,
`editted_by` int(11) DEFAULT NULL,
`editted_date` bigint(20) DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `city_id` (`city_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=179327 ;
CREATE TABLE IF NOT EXISTS `practice_place` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(75) NOT NULL,
`statement` text,
`address` varchar(200) NOT NULL,
`phone` varchar(15) NOT NULL,
`fax` varchar(15) NOT NULL,
`email` varchar(50) NOT NULL,
`village_id` varchar(50) NOT NULL,
`sub_district_id` varchar(50) NOT NULL,
`province_id` varchar(50) NOT NULL,
`zipcode` varchar(10) NOT NULL,
`website` varchar(50) NOT NULL,
`latitude` double NOT NULL,
`longitude` double NOT NULL,
`type` int(11) NOT NULL,
`managed_by` int(11) DEFAULT '0',
`doctor_group_id` int(11) NOT NULL,
`category` varchar(50) NOT NULL,
`photo_file` char(36) NOT NULL,
`is_branch` int(11) NOT NULL,
`parent_id` int(11) NOT NULL,
`editted_by` int(11) NOT NULL,
`editted_date` bigint(20) NOT NULL,
`status` int(11) NOT NULL,
PRIMARY KEY (`id`),
KEY `village_id` (`village_id`),
KEY `doctor_group_id` (`doctor_group_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=25557 ;
CREATE TABLE IF NOT EXISTS `ref_doctor_practice_place` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`doctor_id` int(11) NOT NULL,
`practice_place_id` int(11) NOT NULL,
`is_primary` int(11) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `doctor_id_2` (`doctor_id`,`practice_place_id`),
KEY `doctor_id` (`doctor_id`),
KEY `practice_place_id` (`practice_place_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=38840 ;
有人看到我没看到的内容吗？
答案 0 :(得分：0)
你cannot use column alias in the WHERE clause。因此，您应该使用HAVING，或者想一种不同的方式来过滤您的查询。
答案 1 :(得分：0)
您可以按照以下方式使用别名来应用您的条件，但在考虑以下重点之后 -
Point1：左连接后没有内连接的逻辑，如果你想在左连接后使用内连接，可以使用内连接进行子查询，因为任何特定的原因。
第2点：您应该正确指定OR条件，无论是第二个条件还是两个条件，都要尝试用括号区分它。
SELECT SQL_CALC_FOUND_ROWS D.id * -1 AS id,
D.doc_title AS doc_title, NULL AS user_email, D.first_name,
D.last_name, S.name AS spc_name, S.short_desc AS spc_short_desc,
GROUP_CONCAT(DISTINCT(S2.designation) SEPARATOR ', ') AS spc_dsg,
GROUP_CONCAT(DISTINCT(EM.designation) SEPARATOR ', ') AS em_dsg,
GROUP_CONCAT(DISTINCT(EF.designation) SEPARATOR ', ') AS ef_dsg,
D.gender, 0 AS dob, 0 AS rating, 0 AS no_of_rating, NULL AS photo_file,
NULL AS verification_status, 0 AS rating_score, PP.id AS pp_id,
CONCAT_WS('#', PP.id, PP.name) AS pp_name,
CONCAT_WS('#', PP.id, PP.address) AS pp_address,
CONCAT_WS('#', PP.id, PP.phone) AS pp_phone,
CONCAT_WS('#', PP.id, V.name)AS pp_vil,
CONCAT_WS('#', PP.id, SD.name) AS pp_sub_d,
CONCAT_WS('#', PP.id, C.name) AS pp_city,
CONCAT_WS('#', PP.id, P.name) AS pp_province,
CONCAT_WS('#', PP.id, PP.zipcode) AS pp_zip,
1 pp_is_primary,
CONCAT_WS('#', PP.id, PP.latitude) AS pp_lat,
CONCAT_WS('#', PP.id, PP.longitude) AS pp_lng,
CONCAT_WS('#', PP.id, PP.type) AS pp_type,
CONCAT_WS('#', PP.id, IF(PP.latitude <> 0 AND PP.longitude <> 0, ( 6371 * ACOS( COS( RADIANS(3.5951956) ) * COS( RADIANS( PP.latitude ) ) * COS( RADIANS( PP.longitude ) - RADIANS(98.6722227) ) + SIN( RADIANS(3.5951956) ) * SIN( RADIANS( PP.latitude ) ) ) ), 0)) AS pp_distance, IF(PP.latitude <> 0 AND PP.longitude <> 0, ( 6371 * ACOS( COS( RADIANS(3.5951956) ) * COS( RADIANS( PP.latitude ) ) * COS( RADIANS( PP.longitude ) - RADIANS(98.6722227) ) + SIN( RADIANS(3.5951956) ) * SIN( RADIANS( PP.latitude ) ) ) ) , 9999999) AS min_pp_distance,
NULL AS dp_week, NULL AS 'comment', D.status AS reg_status
FROM register_doctor D
LEFT JOIN ref_doctor_practice_place RDPP ON RDPP.doctor_id = D.id * -1
LEFT JOIN practice_place PP ON PP.id = RDPP.practice_place_id
LEFT JOIN village V ON V.id = PP.village_id
LEFT JOIN sub_district SD ON SD.id = PP.sub_district_id
LEFT JOIN city C ON C.id = SD.city_id
INNER JOIN province P ON P.id = PP.province_id
INNER JOIN city RDC ON RDC.id = D.city_id AND RDC.name LIKE '%Medan%'
INNER JOIN province RDP ON RDP.id = RDC.province_id AND ( RDP.name LIKE 'Sumatera Utara%' OR RDP.long_name LIKE 'Sumatera Utara%' )
INNER JOIN ref_doctor_specialty RDS ON RDS.doctor_id = (D.id * -1) AND RDS.is_primary = 1
INNER JOIN specialty S ON S.id = RDS.specialty_id
INNER JOIN ref_doctor_specialty RDS2 ON RDS2.doctor_id = (D.id * -1)
INNER JOIN specialty S2 ON S2.id = RDS2.specialty_id
LEFT JOIN ref_doctor_education RDE ON RDE.doctor_id = (D.id * -1)
LEFT JOIN edu_magister EM ON RDE.type = 4 AND EM.id = RDE.ref_edu_id
LEFT JOIN edu_fellowship EF ON RDE.type = 5 AND EF.id = RDE.ref_edu_id
GROUP BY D.id
HAVING D.status = 2 AND min_pp_distance < 50 OR min_pp_distance = 9999999
ORDER BY min_pp_distance ASC, RAND()
LIMIT 0,10