我试图在点击一个jbutton的同时播放六个音轨,但点击它会播放第一首曲目并等到它完成播放第二首曲目,依此类推。这是我的代码
button.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
if (e.getSource() == button) {
System.out.println("Button Pressed");
AudioPlayerExample2 player1 = new AudioPlayerExample2();
AudioPlayerExample2 player2 = new AudioPlayerExample2();
AudioPlayerExample2 player3 = new AudioPlayerExample2();
AudioPlayerExample2 player4 = new AudioPlayerExample2();
AudioPlayerExample2 player5 = new AudioPlayerExample2();
AudioPlayerExample2 player6 = new AudioPlayerExample2();
player1.play(track1);
player2.play(track2);
player3.play(track3);
player4.play(track4);
player5.play(track5);
player6.play(track6);
}
}
});
并导入音频播放器
public class AudioPlayerExample2 {
private static final int BUFFER_SIZE = 4096;
public void play(String audioFilePath) {
File audioFile = new File(audioFilePath);
try {
AudioInputStream audioStream = AudioSystem.getAudioInputStream(audioFile);
AudioFormat format = audioStream.getFormat();
DataLine.Info info = new DataLine.Info(SourceDataLine.class, format);
SourceDataLine audioLine = (SourceDataLine) AudioSystem.getLine(info);
audioLine.open(format);
audioLine.start();
System.out.println("Playback started.");
byte[] bytesBuffer = new byte[BUFFER_SIZE];
int bytesRead = -1;
while ((bytesRead = audioStream.read(bytesBuffer)) != -1) {
audioLine.write(bytesBuffer, 0, bytesRead);
}
audioLine.drain();
audioLine.close();
audioStream.close();
System.out.println("Playback completed.");
} catch (UnsupportedAudioFileException ex) {
System.out.println("The specified audio file is not supported.");
ex.printStackTrace();
} catch (LineUnavailableException ex) {
System.out.println("Audio line for playing back is unavailable.");
ex.printStackTrace();
} catch (IOException ex) {
System.out.println("Error playing the audio file.");
ex.printStackTrace();
}
}
public static void main(String[] args) {
String audioFilePath = "";
AudioPlayerExample2 player = new AudioPlayerExample2();
player.play(audioFilePath);
}}
在播放曲目时,按钮也会一直被点击,因此我也无法使用我的音量jslider。谢谢你的帮助!
答案 0 :(得分:0)
你编写play
方法的方式,它将阻塞直到流完全播放 - 这意味着流将一个接一个地播放。一种选择是为每个流分叉一个新线程。这将避免阻塞问题,但会引入另一个问题,那就是线程将全部启动。这意味着流并非都必须在完全相同的时间开始(尽管您可以使用信号使它们非常接近同步)。
我认为更好的方法是使用所有文件中的读取并在单个线程中写入 one SourceDataLine。这意味着您必须自己手动混合信号。假设您的所有文件具有相同的采样率和位深度,那么这并不困难。我假设有16位样本。如果您的文件不同,那么您可以弄清楚如何处理它。
public void play(String[] audioFilePath) {
int numStreams = audioFilePath.length;
// Open all of the file streams
AudioInputStream[] audioStream = new AudioInputStream[numStreams];
for (int i = 0; i < numStreams; i++)
audioStream[i] = AudioSystem.getAudioInputStream(audioFile);
// Open the audio line.
AudioFormat format = audioStream[0].getFormat();
DataLine.Info info = new DataLine.Info(SourceDataLine.class, format);
SourceDataLine audioLine = (SourceDataLine) AudioSystem.getLine(info);
audioLine.open(format);
audioLine.start();
while (true) {
// Read a buffer from each stream and mix into an array of
// doubles.
byte[] bytesBuffer = new byte[BUFFER_SIZE];
double[] mixBuffer = new double[BUFFER_SIZE/2];
int maxSamplesRead = -1;
for (int i = 0 ; i < numStreams; i++)
{
int bytesRead = audioStream.read(bytesBuffer);
if (bytesRead != -1) {
int samplesRead = bytesRead/2;
if (samplesRead > maxSamplesRead) {
maxSamplesRead = samplesRead;
}
for (int j = 0 ; j < bytesRead/2 ; j++) {
double sample = ((bytesBuffer[j*2] << 8) | bytesBuffer[j*2+1]) / 32768.0;
mixBuffer[j] += sample;
}
}
}
// Convert the mixed samples back into a byte array and play.
if (maxSamplesRead > 0) {
for (int i = 0; i < maxSamplesRead; i++) {
// rescale data between -1 and 1
mixBuffer[i] /= numStreams;
// and now back to 16-bit
short sample16 = (short)(mixBuffer * 32768);
// and back to bytes
bytesBuffer[i*2] = (byte)(sample16 >> 8);
bytesBuffer[i*2+1] = (byte)(sample16);
}
audioLine.write(bytesBuffer, 0, maxSamplesRead*2);
}
else {
// All of the streams are empty so cleanup.
audioLine.drain();
audioLine.close();
for (int i = 0 ; i < numStreams; i++)
audioStream[i].close();
break;
}
}
}
通过传递一个文件名数组来调用它(我建议将其替换为track1,track2等...)
button.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
if (e.getSource() == button) {
System.out.println("Button Pressed");
AudioPlayerExample2 player = new AudioPlayerExample2(allTracks);
}
}
});
可能更好的第三种选择是从InputStream
派生一个支持多个文件的类,并在内部进行混合。使用这种方法,您可以使用大多数现有的AudioPlayerExample2
类,但只有一个实例。它会比我现在想要的更多参与。
P.S。我没有尝试编译任何这些。我只是试图理解这个想法。