我一直在寻找这个剧本。 有没有人知道我可以使用鼠标拖动事件旋转图像的任何此类脚本。使用javascript。
提前感谢。
答案 0 :(得分:2)
答案 1 :(得分:0)
我有一个想法,因为我还需要写这个,除非你已经有了解决方案,所以我想拥有它:)
无论如何,这样做:
/ **编辑:删除我的伪代码,转而支持真正的提前** /
无论如何......我会实现这个并告诉你。 除非当然,在接下来的几个小时内,有人会发送他的实施:-) / **编辑:感谢那些做过** /
的人更新: 无论如何,它是旋转一个图像在另一个上面:) 它工作得很好,如果你要导入它,请稍微清理一下。 它是跨浏览器。
HTML:
<div id="centered" style=" /* margin-left:400px; computed in javacript*/ ">
<img id="static" src="" style="position:absolute; z-index:-1">
<img id="rotating" src="" >
</div>
包括:
// jquery.min.js, jQueryRotate.js (discussed above)
的javascript:
var alpha=0
var dragOrig = null
var mouseInPic = new Point(0,0)
var diff
var imageNo = 0
function swapImage_or_something(i /* or get src from somewhere else*/) {
$("#static").attr("src", arrCfgImages[i].src)
$("#rotating").attr("src", arrCfgImages[i].src)
$("#static").height(450);
$("#rotating").height(450);
$("#centered").css ({
"margin-left": ($(document).width()-$("#static").width())/2
})
$("#rotating").rotate(0)
}
function doEventBinding() {
$(document).bind("mousedown", function (e) {
dragOrig = new Point (mouseInPic.x, mouseInPic.y)
e.preventDefault()
return
});
$(document).bind("mouseup", function (e) {
if (dragOrig) {
dragOrig = null
alpha+=diff
diff=0
}
});
$(document).bind("mousemove", function (e) {
var x = -1*(Math.round($("#rotating").width()/2+0.01) - (e.pageX - $("#rotating").offset().left - (isIE ? 2 : 0)))
var y = Math.round($("#rotating").height()/2+0.01) - (e.pageY - $("#rotating").offset().top - (isIE ? 2 : 0))
mouseInPic = new Point(x,y)
if (dragOrig) {
var cp = new Point(0,0)
var deg1 = getAngleBetweenPoints(dragOrig, cp)
var deg2 = getAngleBetweenPoints(mouseInPic, cp)
diff = (deg1-deg2)
diff = diff<0 ? diff+360 : diff>360 ? diff-360 : diff
diff = diff>180 ? diff-360 : diff
//my$("debug").innerHTML = diff
$('#rotating').rotate(alpha+diff);
e.preventDefault()
}
});
}
还:
var toRAD = 1/180*Math.PI;
var toDEG = 180/Math.PI;
function getAngle(dx,dy) {
var ang
if (dx!=0) {
var rad = Math.atan(dy/dx) + (dx<0?Math.PI:0)
ang = rad*toDEG
if (ang<0) ang+=360;
} else {
ang = dy>0 ? 90 : 270;
}
return ang;
}
function getAngleBetweenPoints (p1, p2) {
var dx = p1.x-p2.x
var dy = p1.y-p2.y
return getAngle (dx, dy)
}
答案 2 :(得分:0)
Greensock有一个非常奇特的旋转功能。看一下: https://www.greensock.com/draggable/ 向下滚动旋转。 不幸的是,它并非完全免费。
答案 3 :(得分:-1)
你去吧。这是我的解决方案,它只适用于IE版本的FF版本,你可以找到与FF和其他浏览器中的vml对象相同的东西:
<META HTTP-EQUIV="MSThemeCompatible" CONTENT="yes">
<HEAD>
<script>
var dragok = false;
var gotElementSelected = false;
var currentElement = null;
function move()
{
if (dragok)
{
tempX = event.clientX + document.body.scrollLeft;
tempY = event.clientY + document.body.scrollTop;
//rotating
document.getElementById(currentElement).style.rotation=tempX+tempY;
return false;
}
}
function down(){
dragok = true;
if(gotElementSelected && currentElement !=null)
{
document.onmousemove = move;
return false;
}
}
function up()
{
if(gotElementSelected && currentElement !=null)
{
gotElementSelected = false;
dragok = false;
document.onmousemove = null;
currentElement = null;
}
}
</script>
<STYLE>.rvml {
BEHAVIOR: url(#default#VML)
}
</STYLE>
</HEAD>
<BODY bgcolor=DDDDDD>
<?xml:namespace prefix = rvml ns = "urn:schemas-microsoft-com:vml" />
<rvml:image style="POSITION: absolute; WIDTH: 100px; DISPLAY: none; HEIGHT: 100px; TOP: 100px; LEFT:100px; rotation: 0" id=myimage class=rvml
onmousedown="gotElementSelected=true; currentElement=this.attributes.getNamedItem('id').value; selectedElement=currentElement;"
onclick="select_element(this.attributes.getNamedItem('id').value); selectedElement=this.attributes.getNamedItem('id').value;"
src = "path/to/your/image" coordsize = "21600,21600"></rvml:image>