在Java中打印出连续字符串的问题

时间:2015-09-22 02:49:47

标签: java

系统会提示用户输入员工数据的值。我选择扫描整行,然后将每个数据分成一个String数组(用空格分隔)。我创建了变量fullName并连接了员工的名字和姓氏,但是当我打印出代码时,它只显示姓氏。我已经对此进行了三个小时的排查,并且没有发现任何语法或逻辑错误,为什么不打印全名?

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import java.util.Scanner;
import java.util.ArrayList;
import java.util.Collections;
/**
 * Employee Record Class
 * 
 * @Theodore Mazer
 * @version 9/8/15
 */
public class EmployeeRecord
{
    ArrayList<String> names = new ArrayList<String>();
    ArrayList<String> taxIDs = new ArrayList<String>();
    ArrayList<Double> wages = new ArrayList<Double>();

private String employeeId = "%03d";
private String taxID;
private double hourlyWage = 0.0;

public ArrayList<String> getNamesArrayList(){ //getter method for employee names
    return names;
}
public ArrayList<String> getTaxIdsArrayList(){ //getter method for tax IDs
    return taxIDs;
}
public ArrayList<Double> getWagesArrayList(){ //getter method for hourly wages
    return wages;
}
public void setEmployeeData(){ //setter method for employee data entry
    Scanner scan = new Scanner(System.in);
    String firstName = "";
    String lastName = "";
    String info = "";
    System.out.println("Enter each employees full name, tax ID, and hourly wage pressing enter each time.  (Enter the $ key to finish)");

    while(!(scan.next().equals("$"))){
        info = scan.nextLine();
        String[] splitString = info.split(" ");
        String fullName = "";
        firstName = splitString[0];
        lastName = splitString[1];
        fullName = firstName + " " + lastName;
        double hWage = Double.parseDouble(splitString[3]);
        names.add(fullName);
        taxIDs.add(splitString[2]);
        wages.add(hWage);
    }
    System.out.println("Employee ID  |  Employee Full Name  |  Tax ID  |  Wage  ");    
        for(int i = 0; i <= names.size() - 1; i++){
            System.out.printf(String.format(employeeId, i + 1) + "          | " + names.get(i) + "               |  " + taxIDs.get(i) + " |  " + wages.get(i));
            System.out.println();
        }
}

}

1 个答案:

答案 0 :(得分:2)

while条件下,您使用next()消耗下一个令牌,在您的情况下,它是第一个名称。

我会对while循环进行两次修改:

while (scan.hasNext()) { // <-- check if there's a next token (without consuming it)
    info = scan.nextLine();
    if (info.trim().equals("$")){ // <-- break if the user wants to quit
        break;
    }
    String[] splitString = info.split("\\s+"); // split on any amount/kind of space using regex-split
    String fullName = "";
    firstName = splitString[0];
    lastName = splitString[1];
    System.out.println(Arrays.toString(splitString));
    fullName = firstName + " " + lastName;
    double hWage = Double.parseDouble(splitString[3]);
    names.add(fullName);
    taxIDs.add(splitString[2]);
    wages.add(hWage);
}
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