Question

What I need to find is the "Edit" link that coincides with the "Test Group" link.

I have tried:

//td[contains(text(),'Edit')]/..//a[text()='Test Group']
//td[contains(., "Edit")]/preceding-sibling::a
//*[contains(text(),'Edit')]//tr/td[contains(., 'Test Group')])[3]

Source HTML:

<td>
  <a class="hovsml" onclick="editGroup(5522); return false;" href="#">Edit</a>
</td>
<td>
   <a class="hovsml" onclick="removeGroup(5522,'Test Group'); return false;" href="#">Delete</a>
</td>
<td>
  <img id="groupText5522" width="16" vspace="0" border="0" hspace="0" height="16" onmouseout="hideGroupList('groupInfoDiv5522');" onmouseover="showGroupList('groupText5522','groupInfoDiv5522');" src="img/group_info.gif" style="position: relative;"/>
  <a class="hovsml" title="Test Group" onclick="popup('GroupInfo.php?id=5522','groupinfo',300,430); return false;" href="#">Test Group</a>
</td>

Answer 1

最强大的方法可能是从包含＆＃34;测试组＆＃34;的所有＆lt; tr＆gt;开始。链接并找到＆＃34;编辑＆＃34;从那里链接：

tr[.//a[text()='Test Group']]//a[text()='Edit']

（假设所有＆lt; td＆gt;都有＆lt; tr＆gt;父母。）

Answer 2

从＆＃34;测试组开始＆＃34;链接，上升两个级别，然后寻找＆＃34;编辑＆＃34;链接：

//a[text()='Test Group']/../../td/a[text()='Edit']

XPath表达式，用于查找<a> inside

2 个答案: