Question

我的查询是这个，php是：

Select * 
from games 
left join players on games.id = players.id

echo "game:" .  $player . ",pass" . $pass...

我知道它不正确的php echo只是写得更快

输出：

game:ost1232,pass:10,desc:Difficulty:Highest,players:Duiski,lad:0region:3;game:ost1232,pass:10,desc:Difficulty:Highest,players:testarn,lad:0,region:3;

但我想要

game:ost1232,pass:10,desc:Difficulty:Highest,players:Duiski.testarn,lad:0,region:3;

代码输出两个游戏结果，但只想输入查询中的玩家，中间有一个点。

Games表：id，游戏，密码，描述，阶梯，区域。
Players：id，player

我想查看加入游戏的玩家

Answer 1

如果用户玩更多游戏，我猜你应该有一个中间表，所以我会有这些表：

games
id
name

players
id
name

player_games
game_id
user_id

我会得到用户的游戏＆＃39; John＆＃39;像这样：

select 
players.name as player_name,
games.name as game_name
from games 
join player_games on player_games.game_id
join players on player_games.user_id = players.id
where players.name='John'

可选：在player_games

上添加唯一键约束

PHP连接查询返回不需要的结果

1 个答案: