Question

我在另一个内部运行一个，但第二个只运行一次为什么以及如何解决它。我也尝试过，但只运行一次。

$sql = "SELECT DISTINCT season FROM search WHERE link = '$getid' Order by id asc";
$result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR);
while ($list = mysql_fetch_assoc($result))
{
    $season = $list['season'];
    $sql = mysql_query("SELECT * FROM search WHERE link = '$getid' and season = '$season'");
    $episodes = mysql_num_rows($sql);
    echo '1st';
    $sqls = "SELECT * FROM search WHERE link = '$getid' and season = '$season' Order by id asc";
    $results = mysql_query($sqls, $conn) or trigger_error("SQL", E_USER_ERROR);
    while ($lists = mysql_fetch_assoc($results))
    {
        $episode = $lists['episode'];
        echo'2nd';
    }
}

Answer 1

您要覆盖变量，使用不同的变量：

$sql = "SELECT DISTINCT season FROM search WHERE link = '$getid' Order by id asc";
$result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR);
while ($list = mysql_fetch_assoc($result))
{
    $season = $list['season'];
    $sql2 = mysql_query("SELECT * FROM search WHERE link = '$getid' and season = '$season'");
    $episodes = mysql_num_rows($sql2);
    echo '1st';
    $sqls = "SELECT * FROM search WHERE link = '$getid' and season = '$season' Order by id asc";
    $results2 = mysql_query($sqls, $conn) or trigger_error("SQL", E_USER_ERROR);
    while ($lists2 = mysql_fetch_assoc($results2))
    {
        $episode = $list2['episode'];
        echo'2nd';
    }
}

PHP - 循环内部循环第二个循环只运行一次

1 个答案: