Question

我正在使用ChannelGroup来广播消息，遗憾的是我还没有找到解决方案来正确处理组中可能的慢接收器。

在网上搜索了很多，但仍然没有弄清楚如何利用channelWritabilityChanged（）或ChannelGroupFutureListener来实现我想要的服务器行为：服务器可以一直保持正常客户端的广播，同时不要写入慢速接收器通道isWritable（）成为现实。

基本服务器通道处理程序如下所示：

public class ServerChannelHandler extends SimpleChannelInboundHandler<String> {
    private ChannelGroup group;

    @Override
    protected void messageReceived(ChannelHandlerContext ctx, String msg) throws Exception {
        BizObject bizObject = doBizLogic(msg);
        group.writeAndFlush(bizObject);
    }
}

非常感谢您的帮助！

Answer 1

我相信你应该按照你的描述实现自己的逻辑：

（伪代码）

For all channel in group
   if channel.isWritable is true => immediate write and flush
   possibility 1) (difficult) else through channel.channelPipeline() get the right handler
      on future channelWritabilityChanged(), write what you need
      you need to handle various things:
        - the message to send, 
        - the possibility the writabilityChanged before your handler is ready to handle this
        - ...
   possibility 2) (easy) else add this channel in a new temporary group
call once the loop is over this group asynchronously as you did
  - group.writeAndFlush(object) in an extra thread (so totally asynchronously) 
  - with a possible extra object (shared by the caller thread and the callee) 
  if you want to know when all messages are effectively sent

如何处理Netty ChannelGroup中的慢接收器

1 个答案: