如何拆分字符串列表以查找Haskell中的所有重复项？

Question

假设我的[String]为["one", "one", "two", "three", "three", "three"]

我如何将此[String]拆分为

的[[String]]

[["one", "one"], ["two"], ["three", "three", "three"]]

感谢您的时间

Answer 1

如果要按照示例输入中的相等性对连续值进行分组，则执行

Prelude> Data.List.group ["one", "one", "two", "three", "three", "three"]                               
[["one","one"],["two"],["three","three","three"]]

否则，您可能希望对列表进行排序以获得彼此相邻的相等值。