Question

我有一个在JSON查询中接收它的数组，需要按字母顺序对数组进行排序。

我设法按字母顺序对数组进行排序，但我无法将此数组拆分为多个部分。

我找到了一个NSDicctionary的例子，但我不知道如何填写它。提前谢谢！

   animals = @{@"B" : @[@"Bear", @"Black Swan", @"Buffalo"],
            @"C" : @[@"Camel", @"Cockatoo"],
            @"D" : @[@"Dog", @"Donkey"],
            @"E" : @[@"Emu"],
            @"G" : @[@"Giraffe", @"Greater Rhea"],
            @"H" : @[@"Hippopotamus", @"Horse"],
            @"K" : @[@"Koala"],
            @"L" : @[@"Lion", @"Llama"],
            @"M" : @[@"Manatus", @"Meerkat"],
            @"P" : @[@"Panda", @"Peacock", @"Pig", @"Platypus", @"Polar Bear"],
            @"R" : @[@"Rhinoceros"],
            @"S" : @[@"Seagull"],
            @"T" : @[@"Tasmania Devil"],
            @"W" : @[@"Whale", @"Whale Shark", @"Wombat"]};

Answer 1

如果这是你回来的阵列

NSArray* animals = @[@"Bear", @"Black Swan", @"Buffalo",@"Camel", @"Cockatoo",@"Dog", @"Donkey",@"Emu",@"Giraffe", @"Greater Rhea",@"Hippopotamus", @"Horse",@"Koala",@"Lion", @"Llama",@"Manatus", @"Meerkat",@"Panda", @"Peacock", @"Pig", @"Platypus", @"Polar Bear",@"Rhinoceros",@"Seagull",@"Tasmania Devil",@"Whale", @"Whale Shark", @"Wombat"];

你可以做这样的事情来获得那本字典

NSArray* alphabets = @[@"A",@"B",@"C",@"D",@"E",@"F",@"G",@"H",@"I",@"J",@"K",@"L",@"M",@"N",@"O",@"P",@"Q",@"R",@"S",@"T",@"U",@"V",@"W",@"X",@"Y",@"Z"];
NSMutableDictionary* indexedAnimals = [NSMutableDictionary dictionary];
for (NSString* letter in alphabets)
{
    NSArray* filteredAnimals = [animals filteredArrayUsingPredicate:[NSPredicate predicateWithBlock:^BOOL(NSString* evaluatedObject, NSDictionary *bindings)
    {
        return [evaluatedObject hasPrefix:letter];
    }]];
    if ([filteredAnimals count])
    {
        indexedAnimals[letter] = filteredAnimals;
    }
}
NSArray* sectionLetters = [[indexedAnimals allKeys] sortedArrayUsingSelector:@selector(localizedCaseInsensitiveCompare:)];

然后配置您的表格视图

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
    return [sectionLetters count];
}

- (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section
{
    return sectionLetters[section];
}

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
    return [indexedAnimals[sectionLetters[section]] count]
}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"CellId" forIndexPath:indexPath];

    NSString *animal = indexedAnimals[sectionLetters[indexPath.section]][indexPath.row];
    cell.textLabel.text = animal;

    return cell;
}

填充从JSON中获取的UITableView表单数组

1 个答案: