Question

我没有收到任何编译错误但是必须存在逻辑错误，因为我的checkWinner方法甚至没有遇到。

这是我的checkWinner方法代码：

  public boolean checkWinner() {
  for (int i=0;i<3;i++){ 
     if ((gameBoard[i][0] == gameBoard[i][1]) && (gameBoard[i][1] == gameBoard[i][2])) { //check every row to find a match
        System.out.println(currentMark + "wins!"); 
     }
     else if ((gameBoard[0][i] == gameBoard[1][i]) && (gameBoard[1][i] == gameBoard[2][i])) { //checks every column to find a match
        System.out.println(currentMark + "wins!");
     }
  }
  if ((gameBoard[0][0] == gameBoard[1][1]) && (gameBoard[1][1] == gameBoard[2][2])) { //checks first diagonal
     System.out.println(currentMark + "wins!");
  }
  else if ((gameBoard[0][2] == gameBoard[1][1]) && (gameBoard[1][1] == gameBoard[2][0])) { //checks second diagonal
     System.out.println(currentMark + "wins!");
  }
  else 
     System.out.println("Tie!");      
  return true;

}

这是我的游戏方法，每次用户进入移动后我都会使用checkWinner检查获胜者。

   public void letsPlay() {
  while (true) {
     displayBoard();
     gameOptions();
     int choice = input.nextInt();
     if (choice == 1) {
        if (addMove(input.nextInt(),input.nextInt())) {
           displayBoard();
           checkWinner();
           whoseTurn();

           System.exit(0);
        }

我不确定我的checkWinners方法是否应该是我的addMove方法的一部分...这是addMove

   public boolean addMove(int row, int column) {
  boolean nonacceptable = true;
  while (nonacceptable) {
     System.out.println("Which row and column would you like to enter your mark? Enter the row and column between 0 and 2 separated by a space.");
     row = input.nextInt();
     column = input.nextInt();
     if ((row >= 0 && row <=2) && (column >= 0 && column <=2)) { //make sure user entered a number between 0 and 2
        if (gameBoard[row][column] != ' ') {
           System.out.println("Sorry, this position is not open!");
        }
        else {
           gameBoard[row][column] = currentMark;
           nonacceptable = false;
        }
     }   
     else 
        System.out.println("That position is not between 0 and 2!");
     }
     return nonacceptable;

}

如何将其合并到addMove方法中或更改它以使其作为自己的方法工作？

Answer 1

看起来当用户输入有效答案时nonacceptable设置为false，以便while(nonacceptable)循环退出。但是你返回nonacceptable（这是假的）意味着支票if (addMove())不会通过（因此checkWinner不会被调用）。您可以尝试将if语句向下移动，如下所示：

addMove();
displayBoard();
if (checkWinner()) {
    System.exit(0);
}
whoseTurn();

但是，只有在游戏获胜或并列时，您才需要将checkWinner更改为true，否则返回false。

Java-如何让我的TicTacToe游戏正确检查获胜者？

1 个答案: