Question

所以我想做的是根据mysql中的日期进行倒计时，并使其在实时模式下进行倒计时，而无需刷新。

代码：

<?php 
    $date = strtotime($row_tournaments['date']);
    $remaining = $date - time();
    $days_remaining = floor($remaining / 86400);
    $hours_remaining = floor(($remaining % 86400) / 3600);
    $minutes_remaining = floor(($remaining % 3600) / 60);
    $seconds_remaining = ($remaining % 60);
    echo "<p>$days_remaining <span style='font-size:.3em;'>dias</span> $hours_remaining <span style='font-size:.3em;'>horas</span> $minutes_remaining <span style='font-size:.3em;'>minutos</span> $seconds_remaining <span style='font-size:.3em;'>segundos</span></p>";
?>

这很好但是我需要刷新，所以我可以看到时间的推移。

$date = strtotime($row_tournaments['date']);

这是根据格式为的数据库确定日期：

2015-10-11 08:15:31

Answer 1

＆＃13;

var initialTime = 194801;//Place here the total of seconds you receive on your PHP code. ie: var initialTime = <? echo $remaining; ?>;

var seconds = initialTime;
function timer() {
    var days        = Math.floor(seconds/24/60/60);
    var hoursLeft   = Math.floor((seconds) - (days*86400));
    var hours       = Math.floor(hoursLeft/3600);
    var minutesLeft = Math.floor((hoursLeft) - (hours*3600));
    var minutes     = Math.floor(minutesLeft/60);
    var remainingSeconds = seconds % 60;
    if (remainingSeconds < 10) {
        remainingSeconds = "0" + remainingSeconds; 
    }
    document.getElementById('countdown').innerHTML = days + "dias " + hours + "horas " + minutes + "minutos " + remainingSeconds+ "segundos";
    if (seconds == 0) {
        clearInterval(countdownTimer);
        document.getElementById('countdown').innerHTML = "Completed";
    } else {
        seconds--;
    }
}
var countdownTimer = setInterval('timer()', 1000);

＆＃13;

<span id="countdown" class="timer"></span>

＆＃13;

Answer 2

最好只在mysql db中插入结束时间，并将变量分配给某些像dis

    $sql = "SELECT endtime FROM post";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
$Row = (mysqli_fetch_assoc($result));
$th = $Row['endtime'];    
}
echo $th
?>

然后使用您的javascript运行像dis

这样的倒计时

//let get todays date here
var today = new Date();
var DD = today.getDate();
var MM = today.getMonth()+1; //January is 0!
var YYYY = today.getFullYear();
//let get the Difference in Sec btw the two dates
var _DateFromDBProgEndDate = '<?php echo $th; ?>';
var ProgEndTime = new Date(_DateFromDBProgEndDate);
var TodayTime = new Date();

var differenceTravel = ProgEndTime.getTime()- TodayTime.getTime() ;
var seconds = Math.floor((differenceTravel) / (1000));
////////////////////////////////
var SecDiffFromToday = seconds;
var seconds = SecDiffFromToday;
function timer() {
    var days        = Math.floor(seconds/24/60/60);
    var hoursLeft   = Math.floor((seconds) - (days*86400));
    var hours       = Math.floor(hoursLeft/3600);
    var minutesLeft = Math.floor((hoursLeft) - (hours*3600));
    var minutes     = Math.floor(minutesLeft/60);
    var remainingSeconds = seconds % 60;
    if (remainingSeconds < 10) {
        remainingSeconds = "0" + remainingSeconds; 
    }
    //document.getElementById('countdown').innerHTML = days + ":" + hours + ":" + minutes + ":" + remainingSeconds;
    document.getElementById('dday').innerHTML = days;
    document.getElementById('dhour').innerHTML =hours;
    document.getElementById('dmin').innerHTML =minutes;
    document.getElementById('dsecond').innerHTML =remainingSeconds;



    if (seconds == 0) {
        clearInterval(countdownTimer);
        document.getElementById('countdown').innerHTML = "Completed";
    } else {
        seconds--;
    }
}
var countdownTimer = setInterval('timer()', 1000);

然后为它分配一个div ID =＆＃34;倒计时＆＃34;

数据库倒计时（日期）

2 个答案: