Question

我正在试图从列表中删除包含＆＃34; @＆＃34;

的所有单词

#!/bin/sh

for i in -1 4.5
do  for j in 0 -2.2
    do  # -- keeps the highly portable printf utility from 
        # interpreting '-' as an argument 
        printf -- "$i" "$j\n" 
    done
done

它返回：

string = "@THISISREMOVED @test2 @test3 @test4 a comment"
splitted = string.split()

for x in splitted:
    if '@' in x:
        splitted.remove(x)

string =' '.join(splitted)
print(string)

我想删除包含＆＃39; @＆＃39;的所有字词。不只是第一个，我怎么能这样做？感谢

Answer 1

在迭代它时，不要从列表中删除值。

string = "@THISISREMOVED @test2 @test3 @test4 a comment"
splitted = string.split()

result = []

for x in splitted:
    if '@' not in x:
        result.append(x)



string =' '.join(result)
print(string)

>>> a comment

Answer 2

正则表达式模块有直接的方法：

>>> import re
>>> r = re.compile('\w*@\w*')
>>> r.sub('',  "@THISISREMOVED @test2 @test3 @test4 a comment")
'    a comment'

分解正则表达式：

r = re.compile('''
               \w* # zero or more characters: a-z, A-Z, 0-9, and _
               @   # an @ character
               \w* # zero or more characters: a-z, A-Z, 0-9, and _
               ''',
               re.VERBOSE)

用for删除字符串中的单词

2 个答案: