Question

我正在尝试检索其中包含双重类型值的JSON数组。但是它显示了这个错误：类型java.lang.double无法转换为JSONOBJECT。这是我的代码：

   public  void searchProfession(){
    String myJson;

        try {
        // 

        // Log.i(getClass().getSimpleName(), "send  task - start");

        HttpParams httpParams = new BasicHttpParams();

        //
        HttpParams p = new BasicHttpParams();
        // p.setParameter("name", pvo.getName());
        p.setParameter("user", "1");

        // Instantiate an HttpClient
        HttpClient httpclient = new DefaultHttpClient(p);
        String url = "http://abh.netai.net/abhfiles/searchProfession.php";
        HttpPost httppost = new HttpPost(url);

        // Instantiate a GET HTTP method
        try {
            Log.i(getClass().getSimpleName(), "send  task - start");
           //fffffffffffffffffffffffffff
            httppost.setHeader("Content-type", "application/json");
            InputStream inputStream = null;
            String result = null;
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();

            inputStream = entity.getContent();
            // json is UTF-8 by default
           BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream, "UTF-8"), 8);
           // BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();

            String line = null;
            while ((line = reader.readLine()) != null)
            {
                sb.append(line + "\n");
            }
            result = sb.toString();

            myJson=result;
            if(inputStream != null)inputStream.close();


            //ffffffffffffffffffffffffffff
            //
            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
            nameValuePairs.add(new BasicNameValuePair("user", "1"));
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            ResponseHandler<String> responseHandler = new BasicResponseHandler();
            String responseBody = httpclient.execute(httppost,
                    responseHandler);
            // Parse
            JSONObject json = new JSONObject(myJson);
            JSONArray jArray = json.getJSONArray("result");
            ArrayList<HashMap<String, String>> mylist =
                    new ArrayList<HashMap<String, String>>();

            for (int i = 0; i < jArray.length(); i++) {
                HashMap<String, String> map = new HashMap<String, String>();
                JSONObject e = jArray.getJSONObject(i);
                String s = e.getString("id");
                String fname = e.getString(First_Name);

                JSONObject jObject = new JSONObject(s);
                map.put("id",s);
                map.put(First_Name,fname);



                mylist.add(map);
                Toast.makeText(MapsActivity.this, "your id is"+s, Toast.LENGTH_SHORT).show();
            }
            Toast.makeText(this, responseBody, Toast.LENGTH_LONG).show();

        } catch (ClientProtocolException e) {
            // TODO Auto-generated catch block

            e.printStackTrace();
        } catch (IOException e) {

            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        // Log.i(getClass().getSimpleName(), "send  task - end");

    } catch (Throwable t) {

        Toast.makeText(this, "Request failed: " + t.toString(),
                Toast.LENGTH_LONG).show();




    }

我尝试过人们提供的多种解决方案，但是不起作用。而且我的json数组在记事本中也没问题。 json数组： { “结果”：[{ “ID”： “34.769669”， “如first_name”： “76”}]}

Answer 1

在你的代码中

，你做

        String s = e.getString("id");

所以现在s = 34.769669。

JsonObject是一个键值Object。你不能只是从“34.769669”创建一个json对象。

就像你在这里一样：

        JSONObject jObject = new JSONObject(s);

就像在做

        JSONObject jObject = new JSONObject("34.769669");

编辑：你甚至没有使用这个对象

    JSONObject jObject = new JSONObject(s);

为什么要创造呢？

java.lng.double的值类型无法转换为JSONOBJECT

1 个答案: