Question

我有两个数组如下

[1]=>Array(
    [ingrediant]=>Array(
        [A]=>Chicken [C]=>TomatoJuice
        )
    [price]=> 100
    )
[2]=>Array(
    [ingrediant]=>Array(
        [A]=>Pork  [C]=>LimeJuice
        )
    [price]=> 50
    )
[3]=>Array(
    [ingrediant]=>Array(
        [B]=>Chille [C]=>TomatoJuice
    )
    [price]=>100

    )
)

和

Array([A]=>Array([name]=>meat [code]=>001)
       [B]=>Array([name]=>Vegetable [code]=>002)
       [C]=>Array([name]=>Juice [code]=>003)
)

First Array显示食物组合和第二阵列显示的成分类型例如，

Chicken + tomatojuice Combo

鸡肉是肉，番茄汁是果汁。我想通过果汁获得结果如下。

>Tomatojuice 
-Meat:Chicken, price:100
-Vegetable:Chille, price:100
>LimeJuice
-Meat:Pork, price:100

如何使用php foreach获得这些结果。我已经尝试了好几次。不管怎么样。

Answer 1

此代码应解决您的问题

基于您的数组声明：

$food_combo[] = array(
    'ingrediant'=> array(
        'A' => 'Chicken',
        'C' => 'TomatoJuice'
        ),
    'price'=>100
);
$food_combo[] = array(
    'ingrediant'=> array(
        'A' => 'Pork',
        'C' => 'LimeJuice'
        ),
    'price'=>50
);
$food_combo[] = array(
    'ingrediant'=> array(
        'B' => 'Chille',
        'C' => 'TomatoJuice'
        ),
    'price'=>100
);
$types['A'] = array('name'=>'meat','code'=>'001');
$types['B'] = array('name'=>'vegetable','code'=>'002');
$types['C'] = array('name'=>'juice','code'=>'003');

以下是算法：

$group_by = 'C';
$combo = $output = array();

foreach($food_combo as $food){

    //array("A","B"....);
    $missed = array_diff(
        array_keys($food['ingrediant']), 
        isset($combo[$food['ingrediant'][$group_by]]) ? 
            $combo[$food['ingrediant'][$group_by]] : array()
    );

    if(count($missed)){
        //remove initial group define as key
        foreach(array_diff($missed,array($group_by)) as $type_code)
        $output[$food['ingrediant'][$group_by]][] =
            $types[$type_code]['name'] . 
            ':' . $food['ingrediant'][$type_code] . 
            ',' . 'price:' . $food['price'];
    }
}
print_r($output);

如何使用两个数组来获取结果的foreach循环

1 个答案: