如何优化此MYSQL查询 - 加入多个表

时间:2015-10-06 09:38:32

标签: mysql sql

我有一个大查询(MYSQL)来连接几个表:

SELECT * FROM
    `AuthLogTable`,
    `AppTable`,
    `Company`,
    `LicenseUserTable`,
    `LicenseTable`,
    `LicenseUserPool`,
    `PoolTable` 

WHERE
    `LicenseUserPool`.`UserID`=`LicenseUserTable`.`UserID` and 
    `LicenseUserTable`.`License`=`LicenseTable`.`License` and 
    LEFT(RIGHT(`AuthLogTable`.`User`, 17), 16)=`LicenseUserPool`.`UserID` and 
    `LicenseUserPool`.`PoolID`=`PoolTable`.`id` and 
    `Company`.`id`=`LicenseTable`.`CompanyID` and 
    `AuthLogTable`.`License` = `LicenseTable`.`License` and 
    `AppTable`.`AppID` = `AuthLogTable`.`AppID` AND 
    `PoolTable`.`id` IN (-1,1,2,4,15,16,17,5,18,19,43,20,3,6,8,10,29,30,7,11,12,24,25,26,27,28,21,23,22,31,32,33,34,35,36,37,38,39,40,41,42,-1)

ORDER BY 
     `AuthLogTable`.`AuthDate` DESC,
     `AuthLogTable`.`AuthTime` DESC

LIMIT 0,20

我使用解释,它提供以下内容:

enter image description here

如何加快速度?在一张大桌子上需要几秒钟。

"显示0到19行(总共20行,查询 3.5825 秒)"

据我所知,查询中使用的字段在每个表中都被编入索引。

AuthLogTable

设置了指数

enter image description here

3 个答案:

答案 0 :(得分:3)

您可以尝试运行此查询,而无需按顺序排列'关于您的数据的条款,看看它是否有所作为(也运行'解释')。如果是,您可以考虑在排序的字段上添加索引/索引。 Using temporary; using filesort;表示临时表已创建然后排序,没有需要时间的索引。

据我所知,join样式没有任何区别,因为无论如何查询都被解析为另一种形式。但是您仍然可能希望使用ANSI连接语法(另请参阅此问题ANSI joins versus "where clause" joins)。

答案 1 :(得分:2)

首先考虑修改您的查询以正确使用JOINS。另外,请确保已将JOIN ON子句,WHERE条件和ORDER BY子句中使用的列编入索引。

select * from `AuthLogTable`
join `AppTable` on `AppTable`.`AppID` = `AuthLogTable`.`AppID`
join  `LicenseTable` on `AuthLogTable`.`License` = `LicenseTable`.`License`
join `Company` on `Company`.`id`=`LicenseTable`.`CompanyID`
join `LicenseUserTable` on `LicenseUserTable`.`License`=`LicenseTable`.`License`
join `LicenseUserPool` on `LicenseUserPool`.`UserID`=`LicenseUserTable`.`UserID`
join `PoolTable`  on `LicenseUserPool`.`PoolID`=`PoolTable`.`id`
where LEFT(RIGHT(`AuthLogTable`.`User`, 17), 16)=`LicenseUserPool`.`UserID`
and `PoolTable`.`id` IN (-1,1,2,4,15,16,17,5,18,19,43,20,3,6,8,10,29,30,7,11,12,24,25,26,27,28,21,23,22,31,32,33,34,35,36,37,38,39,40,41,42,-1)
order by `AuthLogTable`.`AuthDate` desc,  `AuthLogTable`.`AuthTime` desc 
limit 0,20;

答案 2 :(得分:0)

尝试以下查询:

SELECT *
FROM `AuthLogTable`
JOIN `AppTable` ON (`AppTable`.`AppID` = `AuthLogTable`.`AppID`)
JOIN `LicenseUserPool` ON (LEFT(RIGHT(`AuthLogTable`.`User`, 17), 16)=`LicenseUserPool`.`UserID`)
JOIN `LicenseUserTable` ON (`LicenseUserPool`.`UserID`=`LicenseUserTable`.`UserID`)
JOIN `LicenseTable` ON (`AuthLogTable`.`License` = `LicenseTable`.`License`
                        AND `LicenseUserTable`.`License`=`LicenseTable`.`License`)
JOIN `Company` ON (`Company`.`id`=`LicenseTable`.`CompanyID`)
JOIN `PoolTable` ON (`LicenseUserPool`.`PoolID`=`PoolTable`.`id`)
WHERE `PoolTable`.`id` IN (-1,1,2,4,15,16,17,5,18,19,43,20,3,6,8,10,29,30,7,11,12,24,25,26,27,28,21,23,22,31,32,33,34,35,36,37,38,39,40,41,42,-1)
ORDER BY `AuthLogTable`.`AuthDate` DESC, `AuthLogTable`.`AuthTime` DESC LIMIT 0,20
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