返回false时,javascript确认(取消)仍然提交表单

时间:2015-10-07 09:41:26

标签: javascript

当我提交并单击“确定”时,它会继续,但是当我按下"取消"无论如何它提交。我尝试使用此代码但提交和取消按钮仍然执行相同的操作。

model.saveForm = function() {
    var r = confirm("Press a button");
    alert(p);
    if (r == true) {
        x = "You pressed OK!";

        if (!validateRequiredNew()) return;
        model.saving(true);

        // check if group id is needed
        var generatedGroupIdPromise = null;
        // if (model.selectedUsers().length > 1 || model.selectedUsers()[0].selectedRoles().length > 1) {
        generatedGroupIdPromise = $.ajax({
            url: '../_vti_bin/listdata.svc/GroupIdGeneratorList',
            type: "POST",
            contentType: "application/json; charset=utf-8",
            data: "{Title: 'dummy'}",
            processData: false,
            dataType: "json"
        });                         

    } else if (r == false){
        x = "You pressed Cancel!"; 
    }

和aspx页面:

<button data-bind="click: saveForm, visible: !saving()">Submit Request</button>

1 个答案:

答案 0 :(得分:3)

只需将public static void main(String[] args) { Scanner input = new Scanner(System.in); int numberOfStudents = -1; boolean exception = true; do { try { System.out.print("Enter the number of students"); numberOfStudents = input.nextInt(); exception = false; } catch (InputMismatchException e) {} input.nextLine(); } while (exception); int number = 0; while (number <= numberOfStudents) { exception = true; number++; System.out.println("Enter student name"); String studentName = input.nextLine(); int grade; do { try { System.out.println("Enter grade"); grade = input.nextInt(); exception = false; } catch (InputMismatchException e) {} input.nextLine(); } while (exception); // input.nextLine(); } } return false;放入您的方法即可。