Powershell哪里有较慢的搜索对象?

时间:2015-10-08 07:48:34

标签: powershell csv active-directory

我有以下代码:

$HardCatUsers = Import-Csv z:\Scripts\Powershell\Hardcat_People_Export.csv

$ADUsers = Get-ADUser -Filter {enabled -eq $true -and surname -like "*" -and    GivenName -like "*" -and Name -notlike "AD*" -and Name -notlike "LRTM*"} -SearchBase "ou=Production, dc=diti, dc=lr, dc=net" | Sort-Object Surname
foreach ($ADUser in $ADUsers)
{
    if ($ADUser.Name.length -le 8)
    {
        $ADSearch = "$($ADUser.Surname), $($ADUser.GivenName) - $($ADUser.Name.ToUpper())"
        if ($Code = $HardCatUsers | Where {$_.Description -eq $ADSearch})
        {
            #"$($ADSearch) $($Code)"
        } else { 
            "$($ADSearch) NEW"
        }
    }

}

$ hardCatUsers对象只有两列数据,如:

Description                                                     Code                                                          
-----------                                                     ----                                                          
# No Assigned User - ACTIVE #                                   ASSET MANAGEMENT                                              
# No Assigned User - SPARE #                                    NO USER SPARE                                                 

我正在做的是拉回AD用户的过滤列表并格式化三个属性,然后在$ hardcatusers中比较/查找此字符串,如果没有找到只输出字符串。

但是当前的实现在每次查找时似乎都非常慢,即5秒。有没有更优雅的方式来搜索列表中的匹配?

由于

1 个答案:

答案 0 :(得分:0)

我发现使用$ hardcatusers的foreach循环比where

快得多

即:

foreach ($ADUser in $ADUsers)
{
    if ($ADUser.Name.length -le 8)
    {
        $found = $false
        $ADSearch = "$($ADUser.DisplayName) - $($ADUser.Name.ToUpper())"
        foreach ($HardcatUser in $HardCatUsers)
        {
            if ($HardcatUser.Description -eq $ADSearch)
            {
                $found = $true
            }
        }

        if ($found -ne $true)
        {
            $Results = New-Object PSObject -Property (@{
                                Description = $ADSearch
                                Code  = "PE" + $NextCode.ToString("000000")
                    })

            $Result += $Results
            $NextCode = $NextCode + 1               
        }

    }

}