在C#中更快地反转图像

时间:2015-10-08 19:57:58

标签: c# .net colors picturebox invert

我正在使用WinForms。我的表格中有一个图片框。当我在图片框中打开图片时,我可以通过单击按钮来回反转颜色,但我的代码非常慢。我怎样才能提高性能。

   private void Button1_Click(object sender, System.EventArgs e) 
     {
        Bitmap pic = new Bitmap(PictureBox1.Image);
        for (int y = 0; (y 
                    <= (pic.Height - 1)); y++) {
            for (int x = 0; (x 
                        <= (pic.Width - 1)); x++) {
                Color inv = pic.GetPixel(x, y);
                inv = Color.FromArgb(255, (255 - inv.R), (255 - inv.G), (255 - inv.B));
                pic.SetPixel(x, y, inv);
                PictureBox1.Image = pic;
            }

        }

    }

2 个答案:

答案 0 :(得分:0)

万一有人需要VB.NET中的类似代码。

还请注意变量inv.A而不是值255。如果图片框具有透明度,则需要此变量。

    Public Function InvertImageColors(ByVal p As Image) As Image
        Dim pic As New Bitmap(p)
        For y As Integer = 0 To pic.Height - 1
            For x As Integer = 0 To pic.Width - 1
                Dim inv As Color = pic.GetPixel(x, y)
                inv = Color.FromArgb(inv.A, 255 - inv.R, 255 - inv.G, 255 - inv.B)
                pic.SetPixel(x, y, inv)
            Next x
        Next y
        Return pic
    End Function

用法:

    pic.image = InvertImageColors(pic.image)

答案 1 :(得分:-3)

这对我有用......

        private Image InvertingImage(Image source)
    {
        //create a blank bitmap the same size as original
        Bitmap newBitmap = new Bitmap(source.Width, source.Height);

        //get a graphics object from the new image
        Graphics g = Graphics.FromImage(newBitmap);

        // create the negative color matrix
        ColorMatrix colorMatrix = new ColorMatrix(new float[][]
{
    new float[] {-1, 0, 0, 0, 0},
    new float[] {0, -1, 0, 0, 0},
    new float[] {0, 0, -1, 0, 0},
    new float[] {0, 0, 0, 1, 0},
    new float[] {1, 1, 1, 0, 1}
});

        // create some image attributes
        ImageAttributes attributes = new ImageAttributes();

        attributes.SetColorMatrix(colorMatrix);

        g.DrawImage(source, new Rectangle(0, 0, source.Width, source.Height),
                    0, 0, source.Width, source.Height, GraphicsUnit.Pixel, attributes);

        //dispose the Graphics object
        g.Dispose();

        return newBitmap;
    }