Question

我正在尝试将表单值存储在数据库中，但错误的值存储在我的表中mobilenumber字段的数据库中。在表格中，我有以下4个字段。

id（自动增量），

移动电话号码，

运算符，

日期。

当我回音时，值显示正确。

但是在将数据库表中存储移动号码时，我得不到mobilenumber字段的相同值。

我有以下代码。

主页

<?php include "header.php"?>
<body>
<div class="form-group">

    <form  name="myForm" action="invite.php"   method="post" class="elegant-aero" onsubmit="return ValidateForm()" >
        <h1> Congratulations. You have been invited to win Rs 148 Recharge.
            <span>Please fill all the details to get a Rs 148 Recharge.</span>
        </h1>
        <label>
            <span>Mobile Number</span>
            <input name="Mobile" id="mob" type="text"  placeholder="Prepaid Mobile Number" required />
        </label>
        <label>
            <span>Operator</span><select name="Operator">
                <option value="Select Operator">Select Operator</option>
                <option value="Bsnl">BSNL</option>
                <option value="Airtel">Airtel</option>
                <option value="reliance">Reliance</option>
                <option value="Vodafone">Vodafone</option>
                <option value="Videocone">Videocone</option>
                <option value="Aircel">Aircel</option>
                <option value="Telenor">Telenor</option>
                <option value="Idea">Idea</option>
                <option value="Tataindicom">Tataindicom</option>
                <option value="other">Other</option>
            </select>
        </label>
        <label>
            <span>&nbsp;</span>
            <input type="submit" class="button" value="Proceed To Recharge" />
        </label>
    </form>
    <div>
</body>
<?php include "footer.php" ?>
</html>

第2页

<html>
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "recharge_project";
/**$mobile = $_POST['Mobile'];
$operator = $_POST['Operator'];
**/
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

$sql = "INSERT INTO customer (id, mobilenumber, mobileoperator) VALUES ('', '$_POST[Mobile]', '$_POST[Operator]')";

if ($conn->query($sql) === TRUE) {
    echo "datainserteed";
} else {
    echo "Error: " . $sql . "<br>" . $conn->error;
}

$conn->close();
?>
<?php include "header.php"?>
<body xmlns="http://www.w3.org/1999/html">
<div class="form-group">

    <form  class="elegant-aero" >
        <p> Invite your 10 active <span style="color:#FF0000"> WhatsApp Friends</span> <!-- and 3 <span style="color:#FF0000">WhatsApp Groups </span>-->to claim your recharge
        </p>
        <label>

<a class="button1" href="whatsapp://send?text=http://rechargetoday.net || Super Promo offer. Get Rs 148 free recharge. Visit above link to get your recharge.NOTE :Offer valid across India!!" onclick="return myFunction()" >Invite</a>
       </br>
        </label>
  <?php echo"</br>";?>
        <label>
            <a name="finish" type="submit" class="button2" onclick="return aboveTen()">Finished- Inviting 10 friends </a>
        </label>
        <label>


        </label>
    </form>
    <div>


</body>

</html>

我有以下JS代码。

var invite = 0; 
function ValidateForm()
{ 
    var fld= document.forms["myForm"]["Mobile"].value; 
    var phoneno = /^\d{10}$/; 
    if(fld.match(phoneno)) 
    { 
        return true;
    } 
    else
    { 
        alert("Please enter valid number"); 
        return false; 
    }
} 
 function myFunction(){ invite ++; }

当我回复$sql时，我得到了以下查询。

INSERT INTO customer (mobilenumber, mobileoperator) VALUES ( 8574968578, 'Vodafone')

Answer 1

请尝试使用$sql = "INSERT INTO customer (id, mobilenumber, mobileoperator) VALUES ('', '$_POST['Mobile']', '$_POST['Operator']')"; $sql = "INSERT INTO customer (id, mobilenumber, mobileoperator) VALUES ('', '$_POST[Mobile]', '$_POST[Operator]')";。

存储在数据库中的错误值

1 个答案: