Question

我的桌子看起来像这样

Serial   |  Name   | Age
------------------------
   1     |  Aby    | 43
   3     |  Philip | 15
   5     |  Tom    | 65
   6     |  Jacob  | 33
   7     |  Matt   | 13
   11    |  Jerom  | 37

我需要更新此表，以便序列列中的所有价值必须继续，而不会有任何缺失值

Serial   |  Name   | Age
------------------------
   1     |  Aby    | 43
   2     |  Philip | 15
   3     |  Tom    | 65
   4     |  Jacob  | 33
   5     |  Matt   | 13
   6     |  Jerom  | 37
---------------------------

如何在单个更新查询

中实现此目的

Answer 1

你可以这样做：

;with T as (
  select row_number () over (order by Serial) as RN, *
  from yourtable
)
update T
set Serial = RN

Answer 2

你应该这样做：

创建一个结构相同但Primary Key Identity的新表：

CREATE TABLE [dbo].[Z_NEW_TABLE](
    [SERIAL] [bigint] IDENTITY(1,1) NOT NULL,
    [NAME] [varchar](MAX) NULL,
    [AGE] [INT] NULL
CONSTRAINT [PK_Z_NEW_TABLE] PRIMARY KEY CLUSTERED 
(
    [SERIAL] ASC
)WITH (
    PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, 
    ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]

将数据插入新表格

INSERT INTO Z_NEW_TABLE (NAME, AGE)
SELECT NAME, AGE
FROM Z_OLD_TABLE

最后删除旧表并重命名新表

Answer 3

    create table #tmp ( id int, name varchar(100)).

insert into #tmp
select 1,'Kesavan'
union
select 3,'Suyambu'
union
select 5,'Mani'
union 
select 7,'Mahesh'

您需要声明一些变量才能实现这一目标，

declare @Count int =1
update #tmp set  @count = id =@count+1 where id != @count

Answer 4

进行更新的另一种方法 -

CREATE TABLE #updatetable (Serial int,  Name  varchar(10), Age int)
insert into #updatetable
select   1,       'Aby',     43 union all
select      3,       'Philip',  15 union all
   select   5 ,      'Tom',     65 union all
   select   6  ,     'Jacob',   33 union all
   select   7   ,    'Matt'  ,  13 union all
   select   11   ,   'Jerom'  , 37
update #updatetable
set Serial = rn
from (
select Serial,row_number() over(order by Serial) rn 
from #updatetable
) a
inner join #updatetable b on a.Serial = b.serial

Answer 5

PHP。来自新手的回答：

$first_data =mysql_query("SELECT * FROM table");
$total = mysql_num_rows();
if($total > 0){
for($i=1; $i <= $total; $i++){
$fd = mysql_fetch_array($first_data);
$update = mysql_query("UPDATE table SET serial='".$i."' WHERE Name='".$fd['Name']."'");
}
}

在单个更新查询中以串行方式更新表中的所有行

5 个答案: