如何在活动控制器视图中显示Facebook Messenger应用程序以发送消息?

时间:2015-10-16 11:46:25

标签: swift uiactivityviewcontroller facebook-messenger

    func pickerView(sender : UIButton) {
    let message="text"
    let objectsToShare = [message]
    let wsActivity = WhatsAppActivity()


    let activityVC = UIActivityViewController(activityItems: objectsToShare, applicationActivities: [wsActivity])
    activityVC.excludedActivityTypes = [UIActivityTypeAirDrop, UIActivityTypeAddToReadingList,UIActivityTypeCopyToPasteboard,UIActivityTypeSaveToCameraRoll,UIActivityTypePrint]

    self.presentViewController(activityVC, animated: true, completion: nil)
}

我如何使用Facebook Messenger进行相同的操作?

2 个答案:

答案 0 :(得分:2)

就我的研究而言,你不能在FB信使中分享“字符串”。这与FB messenger策略有关(为此丢失链接参考)。要在Facebook Messenger上共享,您的“activityItems:objectsToShare”应包含NSURL。我曾尝试共享多个NSRUL,但它没有成功。

您可以传递一个[String,NSURL]数组,例如:

func pickerView(sender : UIButton) {
     let message="text"
     let url = NSURL(String: "https://www.google.com")!
     let objectsToShare = [message, url]  //this is now an [AnyObject]
     //assuming you are don't have applications to exclude

     let activityVC = UIActivityViewController(activityItems: objectsToShare, applicationActivities: [wsActivity])
     self.presentViewController(activityVC, animated: true, completion: nil) 
} 

您会在共享表中找到whatsapp和FB messenger。但是,FB messenger将仅使用NSURL,并忽略AnyObject数组中的String项。 WhatsApp将显示文本,然后显示链接。

可能能够使用FB SDK执行您想要执行的操作。我个人没试过。

答案 1 :(得分:0)

如果您想在UIActivityViewController中展示Facebook应用 而不是指定任何excludedActivityTypes属性。

因为excludedActivityTypes: [String]? //default is nil。`

所以只需用作

let activityVC = UIActivityViewController(activityItems: objectsToShare, applicationActivities: [wsActivity])

self.presentViewController(activityVC, animated: true, completion: nil)

它会显示所有选项,包括facebook,twitter ext。

相关问题