Question

波兰钻石信息

mysql_connect("localhost","root",""); mysql_select_db("basic");

$order = "select * from polish ";       $result=mysql_query($order);


$a="select sum(total) from polish"; $b=mysql_query($a);


 ?>
<?php echo "Polish Diamonds Information: &nbsp; &nbsp; &nbsp; &nbsp; ";
      echo "<a href='home.html'>Go to main page
      <br><br>";

?>



<table border="1" style="width:50%">

         <tr>
            <th><b>ID</b></th>
            <th><b> Name</b></th>
            <th> <b>Selection</b><br>(40000)</th>
            <th><b>Super Deluxe<br>(35000)</b></th>
            <th><b>1<br>(30000)</b></th>
            <th><b>2<br>(25000)</b></th>
            <th><b>3<br>(20000)</b></th>
            <th><b>4<br>(10000)</b></th>
            <th><b>Total Payment</b></th>
            <th><b>Days</b></th>

                 </tr>



    <?php        while($row = mysql_fetch_array($result) )       {
        echo "<tr>
            <td>".$row['id']."</td>
            <td>".$row['name']."</td>
            <td>".$row['c_sel']."</td>
            <td>".$row['c_sdel']."</td>
            <td>".$row['c_1']."</td>
            <td>".$row['c_2']."</td>
            <td>".$row['c_3']."</td>
            <td>".$row['c_4']."</td>
            <td>".$row['total']."</td>
            <td>".$row['day']."</td>
         </tr>";         }

?>    </html>

Answer 1

试试这个循环

$sum_val=0;
while($row = mysql_fetch_array($result) )       {
    echo "<tr>
        <td>".$row['id']."</td>
        <td>".$row['name']."</td>
        <td>".$row['c_sel']."</td>
        <td>".$row['c_sdel']."</td>
        <td>".$row['c_1']."</td>
        <td>".$row['c_2']."</td>
        <td>".$row['c_3']."</td>
        <td>".$row['c_4']."</td>
        <td>".$row['total']."</td>
        <td>".$row['day']."</td>
     </tr>";
     $sum_val+=$row['total'];
     }

     echo"Last column total= $sum_val";

Answer 2

你通过这种方式试试

$order = "select *, sum(c_sel+c_sdel+c_1+c_2+c_3+c_4) as total from polish GROUP BY id "; $result=mysql_query($order);

显示最后一列的总和

2 个答案: