Question

我想将以下两个查询合并到一个查询中，然后查询子查询。第一个查询：

Select Match_ref, WBE Into Match_ref_Confilct
From RAW_MWBE
where WBE="p" or WBE="n"
group by Match_ref, WBE

第二次查询：

Select Match_ref, count(Match_ref)
from Match_ref_conflict

这样做的目的是最终得到一个不止一次出现的match_refs列表，因此存在信息冲突。我试过这个没有成功：

Select match_Ref, count(match_ref)
From RAW_MWBE
where Exists( Select match_ref, WBE
from RAW_MWBE
where WBE like "P" or WBE like "N")
group by match_ref, WBE
having Count(Match_ref)>1

访问SQL

Answer 1

Select Match_ref, count(*) as cnt
From RAW_MWBE
where WBE="p" or WBE="n"
group by Match_ref
having count(*) > 1

Answer 2

您可以大大简化您想要做的事情：

Select Match_ref, count(Match_ref)
from RAW_MWBE
where WBE in ("p", "n")
group by Match_Ref
having min(WBE) <> max(WBE);

这不使用count()，因为您似乎在意“p”和“n”是否一起发生（根据您的查询示例）。

两个查询到一个子查询中

2 个答案: