仅显示来自多个数组值的单个记录

Question

我从api获取数据，我只需要获取相同值的数据一次。例如。 “Test Storage”将来3次，我需要只显示它的第一个记录，并且同样适用于步行顶部和步行中间。这是xml数组的格式

我正在提取数据

SimpleXMLElement Object
(
    [R_Code] => 1
    [sTypeName] => Test Storage
    [iDefLeaseNum] => 1

)
SimpleXMLElement Object
(
    [R_Code] => 1
    [sTypeName] => Test Storage
    [iDefLeaseNum] => 2
)
SimpleXMLElement Object
(
    [R_Code] => 1
    [sTypeName] => Test Storage
    [iDefLeaseNum] => 1
)SimpleXMLElement Object
(
    [R_Code] => 1
    [sTypeName] => Walk Middle
    [iDefLeaseNum] => 1
)SimpleXMLElement Object
(
    [R_Code] => 1
    [sTypeName] => Walk Top
    [iDefLeaseNum] => 1
)SimpleXMLElement Object
(
    [R_Code] => 1
    [sTypeName] => Walk Top
    [iDefLeaseNum] => 1
)SimpleXMLElement Object
(
    [R_Code] => 1
    [sTypeName] => Walk Middle
    [iDefLeaseNum] => 1
)



  foreach($formatUnits->NewDataSet->Table as $unit)
   {
    echo $unit->iDefLeaseNum;
    echo $unit->sTypeName;
   }

Answer 1

您必须使用array_unique()函数从数组中删除重复的元素。
请查看此链接：http://php.net/manual/en/function.array-unique.php

Answer 2

存储值并在输出之前检查它是否存在。

$arr = array();
foreach($formatUnits->NewDataSet->Table as $unit){
    if(! isset($arr[$unit->sTypeName]) ){
        $arr[$unit->sTypeName] = $unit->iDefLeaseNum;
        echo $unit->iDefLeaseNum;
        echo $unit->sTypeName;
    }
}