Question

我有一个小的PHP程序，应该计算Car对象的燃料，里程等。我得到了很好的输出，除了＆＃34;里程＆＃34;部分。它覆盖了原始内容，因此我得到的每段总数而不是总里程数。

我是新手，所以我确信这很简单。提前谢谢。

   <html>
    <head>
        <meta charset="UTF-8">
        <title></title>
    </head>
    <body>
        <?php

        class Car{


            private $fuel = 0;
            private $mpg = 0;
            private $miles = 0;
            private $spentGas = 0;


            public function __construct($initialGas, $mpg){
                $this->fuel = $initialGas;
                $this->mpg = $mpg;

            }
            public function drive($miles){

              if ($miles < ($this->fuel * $this->mpg)){
              $this->miles = $miles;
              } else {
              $this->miles = ($this->fuel * $this->mpg);
              }  

              $this->fuel = ($this->fuel) - ($this->miles / $this->mpg);  
                     ($this->miles / $this->mpg)*($this->mpg);
            }
            public function addGas($gallons){
                $this->fuel = $this->fuel + $gallons;

            }
            public function readFuelGauge(){
                $this->fuel = $this->fuel - $this->spentGas;
                if (($this->fuel)> 0){
                return $this->fuel;
                } else {
                    return 0;
                }
            }
            public function readOdometer(){

                return $this->miles;

            }
            public function __toString() {
                return 'Car (gas: ' . $this->readFuelGauge() .
                ', miles: ' . $this->readOdometer() . ')';
            }
        }

        $Car = new Car(20, 25);
        $Car -> drive(25);
        print($Car . '<br />');
        $Car -> drive(1000);
        print($Car . '<br />');
        $Car -> addGas(5);
        $Car -> drive(10);
        print($Car . '<p><hr>');


        echo '<p>';
        var_dump($Car);


        ?>
    </body>
</html>

Answer 1

问题是你的if声明：

if ($miles < ($this->fuel * $this->mpg)){
    $this->miles = $miles;
} else {
    $this->miles = ($this->fuel * $this->mpg);
}

通过调用$this->miles = $miles;覆盖其当前值。

您可以使用+=运算符来添加其值：$this->miles += $miles;

请不要忘记将燃油减少($this->fuel) - ($miles / $this->mpg);，以免造成总里程数。

您也可以将此技术应用于其他语句，例如$this->fuel = $this->fuel + $gallons;变为$this->fuel += $gallons;

无法弄清楚变量为什么不更新

1 个答案: