Question

我正在尝试做练习。在视图页面中，必须显示每个问题和相应的选项。我能够获得所有问题而不是选项。我想我需要传递每个问题ID以显示相应的选项。但我无法做到这一点。根据问题，有人可以帮助我们选择。

控制器代码：

function index() {


    $data['qn']  = $this->questions_model->questions_list();
    foreach($data['qn'] as $row){ 
    $qs_id = $row->qid;
    $data['qn']['$qs_id']= $this->questions_model->option_list($qs_id);
    $data['qq_id'] =  $data['qn']['$qs_id'];


  //print_r($data['qq_id']);
}

    $this->load->view($this->session->userdata('web_view') . '/header', $data);
    $this->load->view($this->session->userdata('web_view') . '/questions_list', $data);
    $this->load->view($this->session->userdata('web_view') . '/footer', $data);

}

型号代码：

function questions_list() { 

$this->db->select('qbank.*,question_category.category_name');
    $this->db->from('qbank');
$this->db->join('question_category','qbank.cid = question_category.cid');
$query = $this->db->get();
    if ($query->num_rows() >= 1) {
        return $query->result();
    } else {
        return false;
    }
}

function option_list($qs_id){
$this->db->select('option_value');
$this->db->from('q_options');
$this->db->where('qid',$qs_id);

$query = $this->db->get();
if ($query->num_rows() >= 1) {
return $query->result();
} else {
return false;
}
}

查看代码：

<form id="profilefrm" class="sky-form" name="profilefrm" method="post">
<ol>
<?php  foreach($qn as $row){ ?>
<li>
<?php echo $row->question; ?>
<ol type="A">
<?php foreach($qq_id as $rows){ ?>
<li><?php echo $rows->option_value; ?></li>
<?php } ?>                              
</ol>  
</li>

<?php } ?>
</ol>
</form>

Answer 1

控制器

'foreach($data['qn'] as $row){ 
 $qs_id = $row->qid;
 $data['qn']['$qs_id']= $this->questions_model->option_list($qs_id);'

模型

  'function option_list($qs_id){
  $this->db->select('option_value');
  $this->db->from('q_options');
  $this->db->where('q_id','$qs_id');
 $this->db->limit(4);
$query = $this->db->get();
 if ($query->num_rows() >= 1) {
    return $query->result();
} else {
    return false;
} '

查看

<li>
<?php echo $row->question; ?>
<ol type="A">
<?php 
$qs_id = $row->qid;
foreach($row['$qs_id'] as $rows){ ?>
<li><?php echo $rows->option_value; ?></li>
<?php } ?>                              
</ol>  
</li>'

如何获得选项？

1 个答案: