具有一对多关系的HQL正在提供＆＃34; ORA-00936：缺少表达式＆＃34;例外

Question

我有两个具有一对多关系的表格如下：

我的实体类和hbm配置如下：

AuditDetail.java

struct

AuditDetail.hbm.xml

public class AuditDetail implements Serializable {

    private static final long serialVersionUID = 1L;
    private String auditId;
    private Timestamp startTime;
    private Timestamp endTime;
    Set auditParameterDataSet;

    public Set getAuditParameterDataSet() {
        return auditParameterDataSet;
    }
    public void setAuditParameterDataSet(Set auditParameterDataSet) {
        this.auditParameterDataSet = auditParameterDataSet;
    }
    public String getAuditId() {
        return auditId;
    }
    public void setAuditId(String auditId) {
        this.auditId = auditId;
    }
    public void setStartTime(Timestamp startTime) {
        this.startTime = startTime;
    }
    public Timestamp getEndTime() {
        return  endTime;        
    }
    public void setEndTime(Timestamp endTime) {
        this.endTime = endTime;
    }   
}

AuditParameter.java

<hibernate-mapping>

    <class name="com.test.AuditDetail" table="AUDITDETAIL" >          

        <id name="auditId" column="AUDITID" type="string" />

         <property name="startTime" type="java.sql.Timestamp">
              <column name="STARTTIME" sql-type="VARCHAR2(50)" />
         </property>

         <property name="endTime" type="java.sql.Timestamp">
              <column name="ENDTIME" sql-type="VARCHAR2(50)" />
         </property>

        <set name="auditParameterDataSet" cascade="all,delete-orphan" lazy="true" inverse="true">
            <key>
                <column name="AUDITID"/>
            </key>
            <one-to-many class="com.test.AuditParameter" />
        </set>

    </class>

</hibernate-mapping>

AuditParameter.hbm.xml

public class AuditParameter {

    private String auditId ;
    private String parameterId;
    private String fieldName ;
    private AuditDetail auditDetail;

    public String getAuditId() {
        return auditId;
    }
    public void setAuditId(String auditId) {
        this.auditId = auditId;
    }
    public String getParameterId() {
        return parameterId;
    }
    public void setParameterId(String parameterId) {
        this.parameterId = parameterId;
    }
    public String getFieldName() {
        return fieldName;
    }
    public void setFieldName(String fieldName) {
        this.fieldName = fieldName;
    }
    public AuditDetail auditDetail() {
        return auditDetail;
    }
    public void setAuditDetail(AuditDetail auditDetail) {
        this.auditDetail = auditDetail;
    }

}

我的hql查询是以下内容：

<hibernate-mapping>

    <class name="com.test.AuditParameter" table="AUDITPARAMETER" >          

         <id name="parameterId" type="string">
              <column name="PARAMETERID" sql-type="VARCHAR2(50)"  />
        </id>

        <many-to-one name="auditDetail" class="com.test.AuditDetail" column="AUDITID" insert="false" update="false" lazy="false">
        </many-to-one>

        <property name="auditId" type="string">
              <column name="AUDITID" sql-type="VARCHAR2(50)" not-null="false" />
        </property>

        <property name="fieldName" type="string">
              <column name="FIELDNAME" sql-type="VARCHAR2(50)" />
        </property>


    </class>
</hibernate-mapping>

但是当我执行此查询时，它会出现以下错误：

  

ORA-00936：缺少表达

以下是我的控制台输出查询被触发。

select a.auditId, a.startTime, a.endTime, a.auditParameterDataSet from AuditDetail a;

根据这个输出，我们可以看到hibernate没有为a.auditParameterDataSet生成列名。为什么会这样？我在哪里做错了？

Answer 1

您必须使用join： -

HQL： -

select a.auditId, a.startTime, a.endTime, auditParameterDataSet from AuditDetail join a.auditParameterDataSet auditParameterDataSet;

标准： -

Criteria criteria = session.createCriteria(AuditDetail.class);
criteria.setFetchMode("auditParameterDataSet", FetchMode.EAGER);