Question

我正在尝试运行以下Geolocation代码，但以下代码返回undefined。请有人指导我吗

当我调用该函数时，例如

警报（verifylocation（））;

它返回undefined。我想在表单验证中使用它

#include <stdio.h>
#include <stdlib.h>
#include <string.h> 
#include <math.h>
#include <time.h>

#define aSize 2000000


double mean(double* mean_array){
    double mean = 0;

    for (int i=0; i<aSize; i++){
        mean = mean + mean_array[i];
    }


    mean = mean/aSize;

    return mean;

}

double stan_dev_seq(double stan_array[], double stan_mean){

    double a = 0;

    for (int i=0; i<aSize; i++){
        a = a + pow((stan_array[i]-stan_mean), 2);
    }

    a = a/aSize;

    a = sqrt(a);

    return a;
}

int pearson_seq(void){

    clock_t begin, end;
    double time_spent;

    begin = clock();

    double *a;
    a = malloc(sizeof(double)*aSize);


    double *b;
    b = malloc(sizeof(double)*aSize);

    double mean_a;
    double mean_b;

    for (int i=0; i<aSize; i++){
        a[i] = sin(i);
        b[i] = sin(i+2);    

    }

    mean_a = mean(a);
    mean_b = mean(b);



    double stan_dev_a = stan_dev_seq(a, mean_a);
    double stan_dev_b = stan_dev_seq(b, mean_b);

    double pearson_numer;

    for(int i=0; i<aSize; i++){
        pearson_numer = pearson_numer + ((a[i]-mean_a)*(b[i]-mean_b));
    }

    pearson_numer = pearson_numer/aSize;

    double pearson_coef = pearson_numer/(stan_dev_a*stan_dev_b);

    printf("%s %G\n", "The Pearson Coefficient is: ", pearson_coef);

    end = clock();

    time_spent = (double)(end - begin) / CLOCKS_PER_SEC;


    printf("%f %s\n", end, "ms");
    printf("%f %s\n", begin, "ms");
    printf("%f %s\n", time_spent, "ms");



    free(a);
    free(b);

    return 0;
}

int main(void) {

    pearson_seq();

return 0;
}

Answer 1

您可以使用以下内容：

            <!DOCTYPE html>
            <html>
            <body>

            <p>Click the button to get your coordinates.</p>

            <button onclick="getLocation()">Try It</button>

            <p id="demo"></p>

            <script>
            var x = document.getElementById("demo");

            function getLocation() {
                if (navigator.geolocation) {
                    navigator.geolocation.getCurrentPosition(showPosition);
                } else { 
                    x.innerHTML = "Geolocation is not supported by this browser.";
                }
            }

            function showPosition(position) {
                x.innerHTML = "Latitude: " + position.coords.latitude + 
                "<br>Longitude: " + position.coords.longitude;  
            }
            </script>

            </body>
            </html>

地理位置代码返回undefined

1 个答案: